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Virty [35]
3 years ago
13

Explain: a camel walks easily on sand surface than a man inspite of the fact that a camel is much heavier than a man

Physics
1 answer:
Usimov [2.4K]3 years ago
4 0
Camels have friction reduced on their feet making it easier to walk.

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Halley's comet orbits the sun roughly once every 76 years. It comes very close to the surface of the Sun on its closest approach
Licemer1 [7]

Answer:

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

3 0
3 years ago
A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

Ff = m*a   where Ff = μ * N    and a = \frac{V^2}{r}=\omega^2*r

N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0
3 years ago
An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to t
navik [9.2K]

Answer:

a)   t = 1.47 h    b) t = 1.32 h

Explanation:

a)  In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

     v = v_{f}f - v_{w}

     v = 585 -32.1

     v = 552.9 km / h

We use the speed ratio in uniform motion

     v = x / t

     t = x / v

     t = 815 /552.9

     t = 1.47 h

b)  We repeat the calculation, but this time the wind is going in the direction of the plane

      v=  v_{f}f - v_{w}

      v 585 + 32.1

      v = 617.1 km / h

      t = 815 /617.1

      t = 1.32 h

4 0
3 years ago
How many neutrons are present in an atom of Iron-54
Flura [38]

there are 28 neutrons present

3 0
3 years ago
The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?
Tamiku [17]
It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.
8 0
3 years ago
Read 2 more answers
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