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Maksim231197 [3]
3 years ago
13

How does atomic number relate to mass number

Physics
1 answer:
drek231 [11]3 years ago
4 0
Mass Number<span>. An element's </span>mass number<span> (A) is the sum of the </span>number<span> of protons and the </span>number<span> of neutrons. ... Protons and neutrons both weigh about one </span>atomic mass<span> unit or amu. Isotopes of the same element </span>will<span> have the same </span>atomic number<span> but different </span>mass numbers<span>.</span>
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If the sign of work is negative,
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An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the f
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Answer:

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From, the given information: we are not given any value for the mass, the proportionality constant and the distance

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Let's recall that:

v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}

Similarly, The equation of mption:

x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})

replacing our assumed values:

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x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})

x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m

\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}

So, when the object hits the ground when x(t) = 1000

Then from above derived equation:

\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}

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By diregarding e^{-(10)t} \ m

1000= 0.981t-0.981

1000 + 0.981 = 0.981 t

1000.981 = 0.981 t

t = 1000.981/0.981

t = 1020.36 sec

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