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1 year ago

I need help with this problem PLEASE HELP

Mathematics

1 answer:

xxTIMURxx [149]1 year ago

7 0

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

<h3>How to Determine the Range and the Domain of a Function?</h3>

In any given graph that represents a function, the possible set of domain values are plotted on the x-axis (horizontal axis), while the possible set of corresponding range values are plotted on the y-axis (vertical axis).

Thus, the set of x-values (input values) on a graph is the domain of the function while the set of y-values (output values) is the range of the function.

In the given graph, the set of x-values are: -5, -3, -1, and 1.

The set of y-values are: -5, -3, -1, and 1.

Therefore:

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

Learn more about the domain and range of a function on:

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Due very soon so if someone could answer soon-ish it would be very helpful and much appreciated <3<3<3

Nikolay [14]

Answer:

1) x+2y+15=0

only know that one soz

Step-by-step explanation:

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3 years ago

Use the points A (4,4) and B(4,-5). Complete the description of segment AB and find its length.

Scrat [10]

Use the points A(4, 4) and B(4, −5)

(1) (a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same

Here in A(4, 4) and B(4, −5) , the x values are same so the segment AB is a Vertical . The length is the difference between y values ( 4 -(-5)) = 9

Segment AB is a Vertical segment that is 9 units long.

(2) Describe the image of segment AB under the transformation

(x, y) ----> (x, 2y)

A(4, 4) -----> (4, 8)

and B(4, −5) ---> (4, -10)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 8 -(-10)) = 18

The image of segment AB is a Vertical segment that is 18 units long.

(3) Describe the image of segment AB under the transformation

(x, y) ----> (x + 2, y)

A(4, 4) -----> (6, 4)

and B(4, −5) ---> (6, -5)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 4 -(-5)) = 9

The image of AB is a Vertical segment

2 units to the right of the original segment that is

9 units long.

5 0

3 years ago

Read 2 more answers

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

Solve the following system x=3 y=3x-1

astraxan [27]

Answer:

x = 3

y = 8

Step-by-step explanation:

Since it gives you x, you need to plug in the number given for it into the equation:

y = 3x - 1

y = 3(3) - 1

y = 9 - 1

y = 8

So now you have, x = 3 and y = 8

5 0

3 years ago

Can you help me with this?

juin [17]

Answer:

Step-by-step explanation:

apply pythagoras theorem

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2 years ago

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