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3 years ago

Will give brainliest, points, and more!!

2 answers:

7 0

Many every day activities lead to global warming because they produce pollution. When gas is burned in a car, it produces carbon dioxide, a Greenhouse gas. It floats up towards the atmosphere, and makes holes in the atmosphere which lets in those harmful UV radiation and sometimes also adds more atmosphere which could turn earth into the next venous. This causes the heat from the sun to get trapped, bouncing from the earth to the atmosphere. The sun doesn't stop producing heat, so the world gets hotter, causing many changes in temperature each decade that goes by.

hope that helped

tino4ka555 [31]3 years ago

4 0

Do you relizes how many activities lead to global warming? When gas is burned in a car, it produces carbon dioxide (a green house gas). The carbon dioxide then floats up towards the atmosphere and becomes part of the atmosphere. This then causes the heat from the sun to get trapped, bouncing from the atmosphere to the earth. The sun will never stop producing heat which will only lead to the world getting hotter as each decade goes by.

Hope this helps you!

You might be interested in

Ionic compounds generally have lower boiling and melting points than covalent compounds.

Anuta_ua [19.1K]

Answer:

The given statement is false.

Explanation:

Ionic bond is formed by strong electrostatic attraction between two atoms having large difference in their electronegativity.This strong electrostatic attraction provide structural stability to the ionic compounds.For example NaCl.

The ionic compounds generally are solid in nature.As a result their melting point and boiling point are higher that covalent compounds as covalent compounds exist in liquid of gaseous state.

3 0

3 years ago

Suppose 0.245 g of sodium chloride is dissolved in 50. mL of a 18.0 m M aqueous solution of silver nitrate.

Bezzdna [24]

Answer:

$\large \boxed{\text{ 0.066 mol/L}}$

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

1. Assemble all the data in one place, with molar masses above the formulas and other information below them.

Mᵣ: 58.44

NaCl + AgNO₃ ⟶ NaNO₃ + AgCl

m/g: 0.245

V/mL: 50.

c/mmol·mL⁻¹: 0.0180

2. Calculate the moles of each reactant

$\text{Moles of NaCl} = \text{245 mg NaCl} \times \dfrac{\text{1 mmol NaCl}}{\text{58.44 mg NaCl}} = \text{4.192 mmol NaCl}\\\\\text{ Moles of AgNO}_{3}= \text{50. mL AgNO}_{3} \times \dfrac{\text{0.0180 mmol AgNO}_{3}}{\text{1 mL AgNO}_{3}} = \text{0.900 mmol AgNO}_{3}$

3. Identify the limiting reactant

Calculate the moles of AgCl we can obtain from each reactant.

From NaCl:

The molar ratio of NaCl to AgCl is 1:1.

$\text{Moles of AgCl} = \text{4.192 mmol NaCl} \times \dfrac{\text{1 mmol AgCl}}{\text{1 mmol NaCl}} = \text{4.192 mmol AgCl}$

From AgNO₃:

The molar ratio of AgNO₃ to AgCl is 1:1.

$\text{Moles of AgCl} = \text{0.900 mmol AgNO}_{3} \times \dfrac{\text{1 mmol AgCl}}{\text{1 mmol AgNO}_{3}} = \text{0.900 mmol AgCl}$

AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.

4. Calculate the moles of excess reactant

Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)

I/mmol: 0.900 4.192 0

C/mmol: -0.900 -0.900 +0.900

E/mmol: 0 3.292 0.900

So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.

5. Calculate the concentration of Cl⁻

$\text{[Cl$^{-}$] } = \dfrac{\text{3.292 mmol}}{\text{50. mL}} = \textbf{0.066 mol/L}\\\text{The concentration of chloride ion is $\large \boxed{\textbf{0.066 mol/L}}$}$

8 0

3 years ago

How can you recognize an alcohol?

gavmur [86]

Answer:

O D. It has an -OH group attached to the end of the molecule.

Explanation:

Some alcohols have hydroxyl group (OH) attached to the end of a molecule and some have it attached as a branch on the molecule

${ \rm{R - OH \: : \: primary \: alcohol \: (1 \degree)}} \\ \\ { \rm{R -(OH) - R {}^{i} \: : secondary \: alcohol \: (2 \degree)}} \\ \\ { \rm{R - R {}^{i} (OH) - R {}^{ii} \: : tertiary \: alcohol \: (3 \degree)}}$

R is aryl or alkyl group
OH is hydroxyl group

5 0

3 years ago

Calculate the molarity of a MgSO4, solution

Gala2k [10]

Answer:

0.058M is molarity of the solution

Explanation:

Molarity is defined as the ratio between the moles of solute (In this case, MgSO₄) and the liters of solution.

In the problem:

Moles MgSO₄: 0.32 moles

Liters solution: 5.5L

Molarity is:

0.32 moles / 5.5L =

0.058M is molarity of the solution

6 0

3 years ago

When the following equilibrium process

ElenaW [278]

Answer:

K(eq) = 15 (2 sig. figs)

Explanation:

Rxn: CO(g) + 2H₂(g) ⇄ CH₃OH(l)

C(eq): 0.150M 0.360M 0.282M

Keq = [CH₃OH(l)]/[CO(g)][H₂(g)]

= (0.282M)/(0.150M)(0.360M)²

= 14.50617284 (calc. ans.)

= 15 (2 sig. figs.)

4 0

3 years ago