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3 years ago

Will give brainliest, points, and more!!

2 answers:

7 0

Many every day activities lead to global warming because they produce pollution. When gas is burned in a car, it produces carbon dioxide, a Greenhouse gas. It floats up towards the atmosphere, and makes holes in the atmosphere which lets in those harmful UV radiation and sometimes also adds more atmosphere which could turn earth into the next venous. This causes the heat from the sun to get trapped, bouncing from the earth to the atmosphere. The sun doesn't stop producing heat, so the world gets hotter, causing many changes in temperature each decade that goes by.

hope that helped

tino4ka555 [31]3 years ago

4 0

Do you relizes how many activities lead to global warming? When gas is burned in a car, it produces carbon dioxide (a green house gas). The carbon dioxide then floats up towards the atmosphere and becomes part of the atmosphere. This then causes the heat from the sun to get trapped, bouncing from the atmosphere to the earth. The sun will never stop producing heat which will only lead to the world getting hotter as each decade goes by.

Hope this helps you!

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) The reaction below is exothermic: 2SO2 (g) O2 (g) 2SO3 (g) Le Cha^ telier's Principle predicts that __________ will result in

Lynna [10]

Answer:

A) increasing the pressure

Explanation:

Given the exothermic reaction:

2SO₂(g) + O₂(g) ↔ 2SO₃(g)

the question asks what will make the number of moles of SO₃(g) to increase.

When an equilibrium is disturbed, the system will shift in order to counteract the change (see Le Chatelier's Principle) So when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles (because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.

The number of moles in the right side is 2 and the number of moles in the left side is 3.

3 0

3 years ago

If a mineral with a density of 6 g/cm3 is broken into 3, what is the density of each new piece?

mamaluj [8]

Answer:

If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 $\frac{g}{cm^{3} }$

Explanation:

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space, the amount of mass per unit volume.

As density is a physical property of matter that is defined as the ratio of an object's mass to its volume, each material or substance has its own density regardless of its size because the ratio between mass and volume is the same.

If a mineral with a density of 6 g/cm3 is broken into 3, the density of each new piece is 6 $\frac{g}{cm^{3} }$

6 0

3 years ago

A local am radio station broadcasts at a wavelength of 349m, calculate the energy of the wavelength at which it is broadcasting?

Juli2301 [7.4K]

Answer:

E = 5.69x10⁻²⁸m

Explanation:

To solve this question we neeed to convert the wavelength in meters to energy in joules using the equation:

E = hc / λ

Where E is energy in joules, h is Planck's constant = 6.626x10⁻³⁴Js

c is light constant = 3.0x10⁸m/s

And λ is wavelength in meters = 349m

Replacing:

E = 6.626x10⁻³⁴Js*3.0x10⁸m/s / 349m

E = 5.69x10⁻²⁸m

5 0

3 years ago

Water carries helpful nutrients to new areas,

den301095 [7]

Answer:

Positive Flood I believe

8 0

3 years ago

Read 2 more answers

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

8 0

3 years ago