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3 years ago

Will give brainliest, points, and more!!

2 answers:

7 0

Many every day activities lead to global warming because they produce pollution. When gas is burned in a car, it produces carbon dioxide, a Greenhouse gas. It floats up towards the atmosphere, and makes holes in the atmosphere which lets in those harmful UV radiation and sometimes also adds more atmosphere which could turn earth into the next venous. This causes the heat from the sun to get trapped, bouncing from the earth to the atmosphere. The sun doesn't stop producing heat, so the world gets hotter, causing many changes in temperature each decade that goes by.

hope that helped

tino4ka555 [31]3 years ago

4 0

Do you relizes how many activities lead to global warming? When gas is burned in a car, it produces carbon dioxide (a green house gas). The carbon dioxide then floats up towards the atmosphere and becomes part of the atmosphere. This then causes the heat from the sun to get trapped, bouncing from the atmosphere to the earth. The sun will never stop producing heat which will only lead to the world getting hotter as each decade goes by.

Hope this helps you!

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Why are ions usually formed during the interaction of metal with nonmetal and not between two metals?

Alik [6]

Explanation:

Ions are always formed when metals and non-metals interact because metals are electropositive. They willing release electrons to non-metals that are electronegative.

This activity results in charge separation. The transfer of electrons from one specie to another is what results in an ionic bond and the precedence of charged particles.

Between non-metals, the electrons are jointly shared. Therefore, there is no charge separation.

7 0

3 years ago

An atom with a high metallic character usually has a ____ electron affinity and a ____ atomic radius.

lianna [129]

Low electron affinity and large atomic radius

Metallic character decreases across a period (from left to right) and increases down a group.

Electron affinity increases from left to right within a period. This is caused by the decrease in atomic radius. Electron affinity decreases from top to bottom within a group. This is caused by the increase in atomic radius.

8 0

3 years ago

How much heat energy is required to melt 75g of ice at 0°C?

Mnenie [13.5K]

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

Q = N x ΔH

where:

Q = heat

N = moles

ΔH = enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:

1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J.

Step 1 : Calculate moles of water

$[ 75g ] x (\frac{1 mol}{18.02g} ) =$

Step 2 : Multiply by enthalpy of fusion

Q = N × ΔH =  [ Step 1 Answer ] × 6.02 =

Step 3 : Convert kJ to J

$[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =$

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get

Q Would Equal ____

4 0

3 years ago

Calculate the frequency of the n=2 line in the lyman series of hydrogen

Alona [7]

Answer:

Approximately $2.47\times 10^{15}\; \rm Hz$ .

Explanation:

The Lyman Series of a hydrogen atom are due to electron transitions from energy levels $n \ge 2$ to the ground state where $n = 1$ . In this case, the electron responsible for the line started at $n = 2$ and transitioned to

A hydrogen atom contains only one electron. As a result, Bohr Model provides a good estimate of that electron's energy at different levels.

In Bohr's Model, the equation for an electron at energy level $n$ (

$\displaystyle - \frac{k\, Z^2}{n^2}$ (note the negative sign in front of the fraction,)

where

$k = 2.179 \times 10^{-18}\; \rm J$ is a constant.

$Z$ is the atomic number of that atom. $Z = 1$ for hydrogen.
$n$ is the energy level of that electron.

The electron that produced the $n = 2$ line was initially at the

$\begin{aligned} &E_{n = 2} \cr &= -\frac{k\, Z^2}{n^2} \cr &= -\frac{2.179 \times 10^{-18} \times 1}{2^2} \cr & \approx -5.4475\times 10^{-19}\; \rm J\end{aligned}$ .

The electron would then transit to energy level $n = 1$ . Its energy would become:

$\begin{aligned} &E_{n = 1} \cr &= -\frac{k\, Z^2}{n^2} \cr &= -\frac{2.179 \times 10^{-18} \times 1}{1^2} \cr & \approx -2.179 \times 10^{-18} \; \rm J\end{aligned}$ .

The energy change would be equal to

$\begin{aligned}&\text{Initial Energy} - \text{Final Energy} \cr &= E_{n = 2} - E_{n = 1} \cr &= -5.4475 \times 10^{-19} - \left(-2.179 \times 10^{-18}\right) \cr & \approx 1.63425\times 10^{-18}\; \rm J \end{aligned}$ .

That would be the energy of a photon in that $n = 2$ spectrum line. Planck constant $h$ relates the frequency of a photon to its energy:

$E = h \cdot f$ , where

$E$ is the energy of the photon.
$h \approx 6.62607015\times 10^{-34}\; \rm J \cdot s$ is the Planck constant.
$f$ is the frequency of that photon.

In this case, $E \approx 1.63425 \times 10^{-18}\; \rm J$ . Hence,

$\begin{aligned} f &= \frac{E}{h} \cr &\approx \frac{1.63425\times 10^{-18}}{6.62607015\times 10^{-34}} \cr & \approx 2.47 \times 10^{15}\; \rm s^{-1}\end{aligned}$ .

Note that $1 \; \rm Hz = 1 \; \rm s^{-1}$ .

6 0

4 years ago

When you have a cold and are infected with the influenza virus, are you the host or the parasite? Host or Parasite

ololo11 [35]

Answer:

host

Explanation:

the virus exploits your cells

3 0

3 years ago

Read 2 more answers