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Slav-nsk [51]
3 years ago
9

A ball is kicked from the ground with an initial speed v0 at an angle θ above the horizontal. Which of the following best descri

bes the magnitudes of the velocity and acceleration of the ball when it reaches the highest point of its trajectory?
Physics
1 answer:
adoni [48]3 years ago
5 0

Answer:

Explanation:

velocity of projection = vo

angle of projection = θ

When the ball is at maximum height, its vertical component of velocity is zero, So it has only the horizontal component of velocity at highest point.

velocity at highest point = vo Cos θ

The acceleration acting on the ball is only the acceleration due to gravity which always acts vertically downward.

So, teh acceleration of the ball at the highest point is g.

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<h2>since weight is measured in newtons, convert the 6 kg to newtons</h2><h3>the formula to convert is kg x 9.807 = N</h3>
  • 6 x 9.807
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hope that helps :))

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How are lasers used to determine the distance from earth to the moon?
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to find the distance:

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Find the weight of an astronaut whose mass is 75 kg on the moon
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We already know the mass is 75kg.
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8 0
3 years ago
A parallel-plate capacitor has square plates that are 8.00cm on each side and 4.20mm apart. The space between the plates is comp
Sergeu [11.5K]

Answer:

U=1.29\times 10^{-7}\ J

Explanation:

Given that

a= 8 cm (square)

A= a ² = 64 cm²

d= 4.2 mm

d₁= 2.1 mm  ,K₁= 4.7

d₂=2.1 mm  , K₂=2.6

We know that capacitance given as

C_1=\dfrac{K_1\varepsilon _oA}{d_1}

C_1=\dfrac{4.7\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_1=1.26\times 10^{-10}\ F

C_2=\dfrac{K_2\varepsilon _oA}{d_2}

C_2=\dfrac{2.6\times 8.85\times 10^{-12}\times 64\times 10^{-4}}{2.1\times 10^{-3}}

C_2=0.701\times 10^{-10}\ F

Net capacitance

C=\dfrac{C_1C_2}{C_1+C_2}

C=\dfrac{1.26\times 10^{-10}\times 0.701\times 10^{-10}}{1.26\times 10^{-10}+0.701\times 10^{-10}}\ F

C=4.5\times 10^{-11}\ F

We know that stored energy given as

U=\dfrac{CV^2}{2}

V= 76 V

U=\dfrac{4.5\times 10^{-11}\times 76^2}{2}\ J

U=1.29\times 10^{-7}\ J

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Dmitrij [34]
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