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Delvig [45]
3 years ago
13

Consider the case in which the clay is launched along Path Y. The sphere of clay is launched with an initial velocity of v0 and

collides with the rod at a distance of l from the pivot. The length of the rod is L. The rotational inertia of the rod about the joint is IR, and the mass of the clay is mc. The clay is considered a point mass. What is the angular speed f of the clay-rod system immediately after the collision
Physics
1 answer:
Helen [10]3 years ago
4 0

Answer:

    w = \frac{m}{ml^2 + I R^2 }  v l

Explanation:

Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved

initial instant. Before the crash

          L₀ = m v l

Final moment. After the collision with the clay stuck to the rod

          L_f = I_{total} w

angular momentum is conserved

         L₀ = L_f

         m v l = I_total w

         w = \frac{m}{I_{total} }  v l

the total moment of inertia is the sum of the moments of inertia of the two bodies

the moment of inertia of the rod is

        I_rod = I R²

        I_total = m l² + IR²

we substitute

          w = \frac{m}{ml^2 + I R^2 }  v l

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kipiarov [429]

Answer:

t₁ - t₂ = 0.0011 s

Explanation:

given,

y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

now,

y m = 6 mm        ω = 600 rad/s

y₁ = + 2.0 mm    y₂ = -2 .0 mm

now,

2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

so,

kx + (600 rad/s)t₁ + Φ = \dfrac{\pi}{180}sin^{-1}(\dfrac{1}{3})......(1)

we have multiplied with π/180 to convert angle into radians

kx + (600 rad/s)t₂ + Φ = \dfrac{\pi}{180}sin^{-1}(-\dfrac{1}{3})......(2)

subtracting both the equation (1)-(2)

600(t₁-t₂) =  \dfrac{2\pi}{180}sin^{-1}(\dfrac{1}{3})

now,

    t₁ - t₂ = 0.0011 s

time does any given point on the string take to move between displacements is equal to 0.0011 s

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4 years ago
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A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

Explanation:

P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole

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V = nRT/P = 1×8.314×273/100 = 22.70m^3

Mass of N2 = 0.4×28 = 11.2kg

Mass of H2 = 0.6×2 = 1.2kg

Mass of mixture = 11.2 + 1.2 = 12.4kg

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Explain how and why water travels through the four Earth systems as it moves through the water cycle
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3 years ago
As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
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Answer:

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Explanation:

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F = Force = mg

When we divide force by area we get pressure

P=\frac{F}{A}\\\Rightarrow P=\frac{mg}{A}\\\Rightarrow P=\frac{51\times 9.81}{1.5\times 10^{-4}}\\\Rightarrow P=3335400\ N/m^2

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