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Karo-lina-s [1.5K]
1 year ago
6

chegg porter averages 21 points per basketball game with a standard deviation of 4.5 points. suppose porter's points per basketb

all game are normally distributed. let x
Mathematics
1 answer:
romanna [79]1 year ago
8 0
Chegg porter averages 21 points per basketball
game with a standard deviation of 4.5 points.
suppose porter's points per basketball game
are normally distributed. let x
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Marcia claims that the GCF for 2x^2, 4xy and 8xy^4 is 8x^2y^4. Is she correct? If not, what is the GCF?
posledela
The GCF is what they all have in common.
2x is the only thing they ALL share.
5 0
2 years ago
Please help, I’ve been stuck on this question for about a hour now.
Hoochie [10]
6x + 5x + (x + 16) + (3x - 1) = 360
11x + x + 16 + 3x - 1
15x + 15 = 360
15x = 345
x = 23


6(23) = 138
((23) + 16) = 39
(3(23) - 1) =68
5(23) = 115

138 + 39 + 68 + 115 = 360
7 0
3 years ago
Quadrilateral ABCD is similar to quadrilateral EFGH. Find the measure of side FG.
dezoksy [38]
59

47 - 11 = 36
23 + 36 = 59

I hope this helps. Brainliest appreciated.
7 0
2 years ago
Read 2 more answers
⚠️help!!⚠️ i’ve been stuck for 15 minutes!
photoshop1234 [79]

Answer:

y=2x−5 is a line

Step-by-step explanation:

Explanation: y=2x−3 is in slope intercept form for a linear equation, y=mx+b , where m is the slope and b is the y-intercept. The y-intercept is the point at which x=0 and y=−3 , which is point (0,−3) You can plot this point on your graph.

5 0
3 years ago
The side of a square is 2.5 cm. Find its perimeter and area.​
Neko [114]

Answer:

Perimeter = 10 cm

Area = 6.25 cm²

Step-by-step explanation:

\bf \: Given :

\sf \: Side  \:  of \:  the \:  square = 2.5 \: cm

\bf \: To \:  find:

\rightarrow \sf \: Perimeter

\sf\rightarrow Area

\bf \: Solution :

\rm \: First \:  w e \:  need \:  to \:  find  \: out  \: the  \: perimeter \:  o f \:  it.

So to find the Perimeter of the square, we'll use this formula :

\boxed{  \sf\longrightarrow \: Perimeter = 4 \times side}

\bf \: Step  \: 1 : \rm \:  Put \:  the  \: value  \: of   \: side \:  of \:  the  \: square :

\sf\longrightarrow \: Perimeter = (4 \times 2.5)cm

\bf \: Step\;2 : \rm Multiply :

\sf\longrightarrow \: Perimeter  = 10 \: cm

Hence, the perimeter would be 10 cm .

\rule{225pt}{2pt}

\sf \: Now,\; let's\; find  \: the  \: Area .

We know that the formula of Area to find the square is,

\boxed{ \sf \longrightarrow \: Area = (side) {}^{2} }

Note : The answer would always be in cm².

\bf Step\;  1  :\rm Put\;  the\; value \; of\;  side \; of \; the\; square :

\sf\longrightarrow{Area} = (2.5) {}^{2}  \: cm {}^{2}

\sf\longrightarrow{Area} = (2.5 × 2.5 ) \: cm {}^{2}

\bf \: Step\;2 : \rm Multiply :

\longrightarrow\sf \: Area = 6.25 \: cm {}^{2}

Hence, the area of the square would be 6.25 cm².

<em>We are done !</em>

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

:D

3 0
2 years ago
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