Answer:
the answer is D, (2,7)
Step-by-step explanation:
Answer:
If you're trying to solve for r. r=35
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
r+2r=105
(r+2r)=105(Combine Like Terms)
3r=105
3r=105
Step 2: Divide both sides by 3.
3r/3 = 105/3
r=35
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Which equation is not equvilant It is c
