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1 year ago

john dalton's original atomic theory contained the following key ideas. which part(s) of these ideas was/were incorrect?

1 answer:

7 0

John Dalton's original atomic theory contained the following key ideas and the incorrect one is that elements are made of tiny indivisible particles called atoms and is denoted as option A.

This is defined as the smallest unit of matter which forms a chemical element and Dalton proposed that it was indivisible which was later proved wrong.

It was later discovered that atom is made up of sub atomic particles such as proton, electron and neutron. This was therefore the reason why option A was chosen as the most appropriate choice.

Read more about Atom here brainly.com/question/6258301

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The options include:

A. elements are made of tiny indivisible particles called atoms

B. Atoms are unchanged in chemical reaction

C. Atoms can join together in whole number ratios to form compounds.

D. The atoms of each element are unique

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How many micrograms (ug) are in 3.4 x 10^-5 ounces (oz)

marysya [2.9K]

Answer:

964ug

Explanation:

The problem here involves converting from one unit to another.

We are to convert from ounces to micrograms.

1ug = 1 x 10⁻⁶g

1oz = 28.35g

So we first convert to grams from oz then take to ug:

Solving:

1oz = 28.35g

3.4 x 10⁻⁵oz will then give 3.4 x 10⁻⁵ x 28.35 = 9.64 x 10⁻⁴g

So;

1 x 10⁻⁶g = 1ug

9.64 x 10⁻⁴g will give $\frac{9.64 x 10^{-4} }{1 x 10^{-6} }$ = 9.64 x 10²ug or 964ug

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2 years ago

How many H2O molecules are contained in 0.0016 moles of the hydrate Na2B4O7.10H2O?

mamaluj [8]

Maybe this example could help you to understand this problem.

https://image.slidesharecdn.com/121howmanyatoms-091201144624-phpapp02/95/12-1-how-many-atoms-17-728....

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3 years ago

Read 2 more answers

Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.

zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:

Boyle's law at constant T, P = 1 / V
Charles's law, at constant P, V = T
Avogadro's law, at constant P and T, V = n

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

$\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm$

Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

$\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC$

Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

$\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol$

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2 years ago

What does it mean for a reaction to release energy?.

8090 [49]

Answer:

exothermic

Explanation:

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2 years ago

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The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:

IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

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3 years ago