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katen-ka-za [31]
3 years ago
14

Which transformation of energy takes place when a slingshot launches a stone? (PE stands for potential energy.) A. elastic PE to

gravitational PE B. elastic PE to kinetic energy C. gravitational PE to elastic PE D. kinetic energy to gravitational PE
Physics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

B. elastic PE to kinetic energy

Explanation:

As we know that when we stretch the slingshot to some distance then the elastic energy is stored into the sling which is given as

U = \frac{1}{2}kx^2

here we know that

k = elastic constant of the sling

x = stretch in the sling

now when we release the sling from that position then the shot will move with certain kinetic energy from it and sling comes to its natural length

so here we can say that elastic potential energy of the sling will convert into kinetic energy of the shot here so correct answer will be

B. elastic PE to kinetic energy

boyakko [2]3 years ago
6 0

B. Elastic potential to kinetic energy

The elastic potential energy in the slingshot will be transferred to the stone as kinetic energy as the stone is launched.

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Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an
Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0
3 years ago
Does the earths magnetic field change with time?
ZanzabumX [31]

Answer:

As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.

6 0
3 years ago
A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
AysviL [449]
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2

So, option B is your answer!

Hope this helps!

7 0
3 years ago
A light ray transfers from more to less dense medium at certain condition , if we repeat this experiment by increasing the angle
evablogger [386]

Answer:

The correct option is;

Still constant

Explanation:

The relative refractive index ₁n₂ between the two medium can be as follows;

_1n_2 = \dfrac{The \ speed \ of \ light \ in \ medium \ 1}{The \ speed \ of \ light \ in \ medium \ 2}  = \dfrac{c_1}{c_2}

Therefore, given that the speed of light in medium 1 is constant and the speed of light on medium 2 is also constant, the relative refractive index ₁n₂ = c₁/c₂ is always constant.

4 0
3 years ago
A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the
mylen [45]

Answer:

Angular acceleration, is 708.07\ rad/s^2

Explanation:

Given that,

Initial speed of the drill, \omega_i=0

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, \omega_f=28940\ rev/min=3030.58\ rad/s

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2

So, the drill's angular acceleration is 708.07\ rad/s^2.

4 0
3 years ago
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