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bonufazy [111]
3 years ago
10

A 20-N falling object encounters 4 N of air resistance. The magnitude of the net force on the object is?

Physics
1 answer:
Irina18 [472]3 years ago
8 0

16-N because 20-4=16

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How does increasing the speed of a motorbike change the amount of energy in its kinetic energy store?
Gnesinka [82]

Answer:

Kinetic energy is energy in motion so therefor if you increase the velocity or in your case speed the kinetic energy also has to increase

Explanation:

4 0
4 years ago
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When performing an.experiment similar to Millikan's oil drop, a student measured the following load magnitudes: 3.26x10 ^-19 C 5
Scilla [17]

Answer:

1.6 x 10⁻¹⁹ C

Explanation:

Let us arrange the charges in the ascending order and round them off as follows :-

1.53 x 10⁻¹⁹ C   → 1.6x 10⁻¹⁹ C

3.26 x 10⁻¹⁹C   → 3.2 x 10⁻¹⁹ C

4.66 x 10⁻¹⁹C   → 4.8 x 10⁻¹⁹ C

5.09 x 10⁻¹⁹C   → 4.8 x 10⁻¹⁹ C

6.39 x 10⁻¹⁹C   → 6.4 x 10⁻¹⁹ C

The rounding off has been made to facilitate easy calculation to come to a conclusion and to accommodate error in measurement.

Here we observe that

2 nd charge is almost twice the first charge

3 rd and 4 th charges are almost 3 times the first charge

5 th charge is almost 4 times the first charge.

This result implies that 2 nd to 5 th charges are made by combination of the first charge ie if we take e as first  charge , 2nd to 5 th charges can be  written as 2e,  3e ,3e and 4e. Hence e is the minimum charge existing in nature and on electron this minimum charge of  1.6 x 10⁻¹⁹ C  exists.

3 0
3 years ago
Help me?!?!?!?!?!?!?!?!?!?!?!?!?!
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The correct field line would be A.
3 0
4 years ago
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A house brick has a volume of 1900 cm³ and a weight in air of 80N.What is its apparent weight in water?The density of water is 1
Shtirlitz [24]

Answer:

61 N

Explanation:

We'll begin by calculating the mass of the brick when placed in water. This can be obtained as follow:

Volume of brick = 1900 cm³

Density of water = 1 g/cm³

Mass of brick in water =…?

Density = mass / volume

1 = mass of brick in water / 1900

Cross multiply

Mass of brick in water = 1 × 1900

Mass of brick in water = 1900 g

Next, we shall convert 1900 g to Kg.

1000 g = 1 Kg

Therefore,

1900 g = 1900 g × 1 Kg / 1000 g

1900 g = 1.9 Kg

Next, we shall determine the weight in water. This can be obtained as follow:

Mass (m) = 1.9 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 1.9 × 10

W = 19 N

Thus, the weight of the brick in water is 19 N.

Finally, we shall determine the apparent weight of the brick in water. This can be obtained as follow:

Weight in air = 80 N

Weight in water = 19 N

Apparent weight =?

Apparent weight = weight in air – weight in water

Apparent weight = 80 – 19

Apparent weight = 61 N

3 0
3 years ago
3.accuracy is gauged by comparing the measured value of a known standard to its true value. assuming the mass of the water repre
tangare [24]

The glassware with the highest degree of accuracy is 250 mL beaker.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Accuracy compares the experimental value to the theoretical value.

Accepted density of water = 0.99 g/mL

1. 10 mL cylinder

Mass of water = 6.76 g

Volume of water = 6.8 mL

Density = mass /Volume

density = 6.76/6.8 = 0.99412 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99412 - 0.99 / 0.99 ] x 100

% error = 0.416 %

2. 50 mL cylinder

Mass of water = 24 g

Volume of water = 24.2 mL

density = 24/24.2 = 0.9917 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9917 - 0.99 / 0.99 ] x 100

% error = 0.172 %

3. 25 mL cylinder

Mass of water = 17 g

Volume of water = 17.1 mL

density = 17/17.1 = 0.99415 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99415 - 0.99 / 0.99 ] x 100

% error = 0.419 %

4. 250 mL beaker

Mass of water = 35 g

Volume of water = 35.3 mL

density = 35/35.3 = 0.9915 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9915 - 0.99 / 0.99 ] x 100

% error = 0.152 %

Lesser the percentage error, higher is the accuracy.

Thus, 250 mL beaker has the highest degree of accuracy.

Learn more about accuracy.

brainly.com/question/13099041

#SPJ1

4 0
2 years ago
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