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balu736 [363]
3 years ago
5

How would you represent 5 eighth notes as a fraction

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0
Well 8th notes are 1/2 a beat long so if you have 5 8th notes well 5*1/2= 2.5 so 2.5 Notes.
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OLga [1]

Answer:

1. 10^(38)

2. total amount = 10^11 or total amount = $100000000000  

Step-by-step explanation:

For every time that we multiply powers with the same base we maintain the base and sum the powers. Therefore we have:

1. (10^32)*(10^6)

10^(32 + 6)

10^(38)

2. If each of the 10^6 programmers make 10^5 then the total money they make together is the product of the number of programs with the sallary each makes. We have:

total = (10^6)*(10^5)

total = 10^(6 + 5)

total = 10^11

total = $100000000000

6 0
3 years ago
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likoan [24]

Answer:

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Step-by-step explanation:

First, let's find term 1. To find this term, we need to replace n with 1 - what is 4(1) - 5? Well, that's just 4 - 5, or -1. So, our first term is -1. Next, we'll find our second term. To do this, we'll replace n with 2. 4(2) = 8, and then 8 - 5 is equal to 3, so our second term is 3. Let's now find the third term by replacing n with the number 3. 4(3) - 5 is equal to 12 - 5, or 7. So, 7 is our third term. Finally, we'll find the fourth term. 4(4) is equal to 16, and 16 - 5 is equal to 11. So, the fourth and final term is equal to 11.

Hopefully that's helpful! :)

5 0
2 years ago
Read 2 more answers
Regina claims that gold has a mass almost 20 times more than water.
Butoxors [25]

The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu, also known as daltons, D). The atomic mass is a weighted average of all of the isotopes of that element, in which the mass of each isotope is multiplied by the abundance of that particular isotope. (Atomic mass is also referred to as atomic weight, but the term "mass" is more accurate.)

7 0
3 years ago
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erma4kov [3.2K]

Answer: Nine less than two thirds of a quantity is smaller than one more than that same quantity.

4 0
3 years ago
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Bingel [31]
We\ know:\\\\\cos(90^o-\alpha)=\sin\alpha\\\\\cos37^o=\cos( 90^o-53^o)=\sin53^o
8 0
3 years ago
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