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2 years ago

Please help and explain. The question is in the picture below.

Mathematics

1 answer:

Murrr4er [49]2 years ago

7 0

Answer:

D and yes

Step-by-step explanation:

$\frac{x}{4}$ + 1 = -3 If we multiply both sides of the equation by 4 will will get the second equation

(4) $\frac{x}{4}$ + (4) 1 = (4) -3

x + 4 = -12 We solve this for x by subtracting 4 from both sides.

x = -16

Plug -7 into both equations and you will see that it is a solution

$\frac{x}{4}$ + 1 = -3

$\frac{-16}{4}$ + 1 = -3

-4 + 1 = -3

-3 = -3

x + 4 = =12

-16 + 4 = -12

-12 - -12

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Which of the following is not true about cluster sampling?

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Answer:

The correct answer is D. It is not true that cluster sampling uses randomly selected clusters and samples everyone within each cluster.

Step-by-step explanation:

Cluster sampling is a method of collecting samples and statistical data, by means of which a certain group formed by people, things, events, etc., is taken as a sample, which are not considered individually but as part of a whole, which is in turn a proportional representation of the universality of samples available in the field.

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3 years ago

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Answer:

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3 years ago

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3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

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3 years ago

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nikitadnepr [17]

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Hope you've drawn a picture, so as to understand this better. ;)

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3 years ago

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