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sammy [17]
2 years ago
8

Please help and explain. The question is in the picture below.

Mathematics
1 answer:
Murrr4er [49]2 years ago
7 0

Answer:

D and yes

Step-by-step explanation:

\frac{x}{4} + 1 = -3  If we multiply both sides of the equation by 4 will will get the second equation

(4) \frac{x}{4}+ (4) 1 = (4) -3

x + 4 = -12  We solve this for x by subtracting 4 from both sides.

x = -16  

Plug -7 into both equations and you will see that it is a solution

\frac{x}{4} + 1 = -3

\frac{-16}{4} + 1 = -3

-4 + 1 = -3

-3 = -3

x + 4 = =12

-16 + 4 = -12

-12 - -12

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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
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Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

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To find the y-int., let x =0 and read off the y-int:  (0, -6)
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