How many grams of NaCl are contained in 0.50 L of a 4.20 M solution?
1 answer:
Answer:
The answer to your question is the third option: 122.7 g of NaCl
Explanation:
Data
mass of NaCl = ?
molecular mass of NaCl = 23 + 35.5 = 58.5
volume = 0.50 l
concentration = 4.20 M
Formula
Moles = Molarity x volume
Process
1.- Substitute the data given to find the moles of NaCl
Moles = 4.20 x 0.5
Moles = 2.1
2.- Calculate the grams of NaCl using proportions
58.5 g of NaCl ----------------- 1 mol
x ---------------- 2.1 moles
x = (2.1 x 58.5) / 1
3.- Result
x = 122.7 g of NaCl
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Answer: Option (c) is the correct answer.
Explanation:
A limiting reagent is defined as a reagent that completely gets consumed in a chemical reaction. A limiting reagent limits the formation of products.
For example, we have given 5 mol of A and the reaction is
Whereas when 4 mol B will react with 2 mol of A. Hence, 8 mol of B will react with 4 mol A as follows.
= 4 mol
As, the given moles of A is more than the required moles. Thus, it is considered as an excess reagent.
Hence, B is a limiting reagent because it limits the formation of products.
Thus, we can conclude that limiting reactant is the term used to describe the reactant that is used up completely and controls the amount of product that can be produced during a chemical reaction.