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djverab [1.8K]
3 years ago
7

How many grams of NaCl are contained in 0.50 L of a 4.20 M solution?

Chemistry
1 answer:
disa [49]3 years ago
8 0

Answer:

The answer to your question is the third option: 122.7 g of NaCl

Explanation:

Data

mass of NaCl = ?

molecular mass of NaCl = 23 + 35.5 = 58.5

volume = 0.50 l

concentration = 4.20 M

Formula

Molarity = \frac{moles}{volume}

     Moles = Molarity x volume

Process

1.- Substitute the data given to find the moles of NaCl

     Moles = 4.20 x 0.5

     Moles = 2.1

2.- Calculate the grams of NaCl using proportions

     58.5 g of NaCl ----------------- 1 mol

        x                     ----------------  2.1 moles

      x = (2.1 x 58.5) / 1

3.- Result

      x = 122.7 g of NaCl      

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hypochlorite ion

Explanation:

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If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,
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Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

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Units: g/cm3

a)

If m1, V1 and D1 = mass, volume  and density respectively of ball A

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It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

b)

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

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c)

If m1, V1 and D1 = mass, volume  and density respectively of ball P

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Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

d)

If m1, V1 and D1 = mass, volume  and density respectively of ball X

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