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Maru [420]
3 years ago
7

Suppose a student completes an experiment with an average value of 2.6 mL and a calculated standard deviation of 0.80 mL. What i

s the minimum value within a 1 SD range of the average
Chemistry
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

Explanation:

1 standard deviation range will look like: [average - SD, average + SD]

Here the miximum value will be: average - SD = 2.6 - 0.80 = 1.80 ml

and the maximum value will be: average + SD = 2.6 + 0.80 = 3.40ml

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What did you observe in the reaction of phosphoric acid with the freshly cleaned zinc when compared with a piece just taken out
mash [69]

Answer:

The classification is mentioned below for the particular topic.

Explanation:

  • Whether we position 2 different beakers in such a single beaker through one clean edge of zinc-containing H₃Po₄ and another one with unflushed zinc.  
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⇒      3Zn+2H_{3}Po_{4}\rightarrow Zn_{3}(Po_{4})_{2}+3H_{2}

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3 years ago
I have these orgo problems for homework and I have no idea where to even begin. We have to find missing reagents and products ba
almond37 [142]

Answer:

Honestly makes no sense sorry :(

Explanation:

I can try though.. There are three types of selectivity possible for any synthesis: (i) Chemoselectivity is deciding which group reacts. (ii) Regioselectivity is where the reaction takes place in that group. (iii) Stereoselectivity is how the group reacts with respect to the stereochemistry of the product.

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I tried to explain it the best I could.

Hopefully this helps you :)

Feel free to correct me If it was wrong

5 0
3 years ago
The temperature of a 500. ml sample of gas increases from 150. k to 350. k. what is the final volume of the sample of gas, if th
maw [93]
<span>pv=nrt; Pressure and moles are constant. p=nr(150k)/.5 L; Pressure initially After temp change pv=nrt; What is volume? v=nr(350k)/p; p is constant so we can substitute from above v=nr(350k)/(nr(150k)/.5 L)) v=350/150/.5 L v=4.66 liters</span>
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3 years ago
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A decrease is the concentration of nitrogen monoxide (blank#1) between NO and H2 molecules. The rate of the forward reaction the
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In the given situation, the reaction is-

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Ans) A decrease in the concentration of nitrogen monoxide decreases the collisions between NO and H2 molecules. the rate of the forward reaction then decreases.

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3 years ago
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amid [387]
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