Question

Suppose a student completes an experiment with an average value of 2.6 mL and a calculated standard deviation of 0.80 mL. What is the minimum value within a 1 SD range of the average

Answer 1

Answer:

Explanation:

1 standard deviation range will look like: [average - SD, average + SD]

Here the miximum value will be: average - SD = 2.6 - 0.80 = 1.80 ml

and the maximum value will be: average + SD = 2.6 + 0.80 = 3.40ml