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2 years ago

The voltage drop across an inductor in a circuit with a dc voltage source at time>> 5*time-constant is:_________

1 answer:

5 0

The voltage drop across an inductor in a circuit with a dc voltage source at time>> 5*time-constant is more than as compared to first case because the voltage across the inductor is proportional to the rate of change of current which is a maximum at the start when the current and the voltage across the resistor are zero.

As time progresses the current increases at a slower rate as does the voltage across the resistor but the voltage across the inductor decreases.

The voltage drop is proportional to the current, which is the rate-change of the charge. Inductors: V = L (DI/Dt). The voltage drop across the inductor is proportional to the rate-change of the current.

<h3>How do you calculate voltage drop in an inductor?</h3>

The formula which calculates the inductor voltage is

V= Ldi/dt,

where,

V is the voltage across the inductor,

L is the inductance of the inductor,

di/dt is the derivative of the current flowing across the inductor.

Thus from the above conclusion we can say that The voltage drop across an inductor in a circuit with a dc voltage source at time>> 5*time-constant is more than as compared to first case because the voltage across the inductor is proportional to the rate of change of current which is a maximum at the start when the current and the voltage across the resistor are zero.

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When the pivot point of a balance is not at the center of mass of the balance, how is the net torque on the balance calculated?

viktelen [127]

Answer:

Explanation:

Net torque is calculated by multiplying the force with distance from the point of application of force to the point of pivot .

If more than 2 forces are present, then we either subtract the product of forces with their respective distances from pivot point or we add them . It depends on whether they both are present on opposite sides of pivot or on same side of pivot .

When a force is applied directly to the pivot point of balance, then the torque on due that force = 0 (zero) .

It is so because the torque is defined as the product of force and perpendicular distance from the pivot point but here the distance is 0 , therefore torque is zero.

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4 years ago

A plane is flying 2400 miles from a to

geniusboy [140]

From a to b speed is 600+40 = 640
from b to a speed is 600-40 = 560

let t be the number of hours of flight. This would mean it would have traveled a distance of 640 miles and the distance yet to travel is 2400-640t
Time left will be (2400-640t)/640. But if they were to return to a it would fly 640t miles at 560mph which will take (640t/560) hrs

(2400-640t) / 640 = 640t / 560
560(2400 - 640t) = 640t x 640
t = 1.75hrs

5 0

4 years ago

A. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by

valina [46]

a. The spring is compressed by 0.174 m.

b. The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is 13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is 13.74 m/s.

d. Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

Learn more about potential energy.

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7 0

2 years ago

Guys help me please gr5 science pls help

Stolb23 [73]

Answer:

just google it.

Explanation:

Because its easier

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4 years ago

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Nikolay [14]

Any like answer choices would be helpful '-'

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3 years ago