The total angular momentum of the system about point B is 
Angular momentum, also known as moment of momentum or rotational momentum, is the rotating counterpart of linear momentum.
A rigid object's angular momentum is defined as the product of its moment of inertia and its angular velocity. If there is no external torque on the object, it is analogous to linear momentum and is subject to the fundamental constraints of the conservation of angular momentum principle. The vector quantity angular momentum It is derived from the expression for a particle's angular momentum.
Given,
mass of ball 1 = m1
m₂ mass of ball 2=m2
v₁ is the velocity of ball=r₁ω₁
v₂ is the velocity of ball 2=r₂ω₂
The total angular momentum is given as;
Hence the total angular momentum will be
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Answer:
Height h = 37.8 m
Explanation:
Given
:
Velocity of car (v) = 98 km / h
Acceleration of gravity = 9.8 m/s²
Computation:
Acceleration of gravity = 9.8 m/s²
Acceleration of gravity = (98)(1,000 m / 3,600 s)
Acceleration of gravity = 27.22 m/s
By using law of conservation of energy
;
(1/2)mv² = mgh
h = v² / 2g
h = 27.22² / 2(9.8)
Height h = 37.8 m
Answer:
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Explanation:8uhhhhhhhhhlkgg
Answer:
<em>The PE of the mass increased by 6,972.95 J</em>
Explanation:
<u>Gravitational Potential Energy</u>
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.
We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:
1 slug = 14.59 Kg, thus
16 slug = 16*14.59 Kg=233.44 Kg
1 ft = 0.3048 m, thus:
10 ft = 10*0.3048 m = 3.048 m
Thus, the PE of the mass increased by:
U = 233.44 * 9.8 * 3.048 = 6,972.95 J
the PE of the mass increased by 6,972.95 J
Hello There!
Relative density is another word for specific gravity. Relative density is comparing the density of one thing to the density of another. Most of the time, you look at the density of water so we look at the density of an object relative to the density of water.
