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3 years ago

12

Calculate the weight of a 5 kg object, if it was on Mercury (where the acceleration due to gravity is 4 m/s2)

1 answer:

melomori [17]3 years ago

7 0

Answer: 20 N

Explanation: W = mg = 5.0 kg · 4.0 m/s²

Weight is dependent on acceleration of gravity on planet

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The CIA investigated hypnosis as a possible tool for interrogating prisoners. Why did they decide it was unsuitable for that

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D. Hypnosis can make the subjects talk, but they talk only about their childhoods.

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BRAINLIEST TO THE CORRECT QUESTION

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Answer:

the answer is B

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3 years ago

Guiana dolphins are one of the few mammals able to detect electric fields. In a test of sensitivity, a dolphin was exposed to th

Y_Kistochka [10]

Answer:

0.05 V/m

Explanation:

For a uniform electric field, electric field strength and potential difference are related by

$E=\frac{\Delta V}{d}$

where

E is the electric field strength

$\Delta V$ is the potential difference

d is the distance between the two points

Here we have

$\Delta V= 0.50 mV=5\cdot 10^{-4}V$

$d=1.0 cm=0.01 m$

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3 years ago

The weight of spaceman Speff at the surface of planet X, solely due to its gravitational pull, is 389 N. If he moves to a distan

9966 [12]

Answer

given,

W = weight of speff at surface of planet = 384 N

h= height = 1.86 x 10⁴ Km

W' = weight of speff at height h from the planet = 24.31 N

Ms = speff mass = 75 kg

M= mass of planet = ?

R = radius of planet

G = 6.67 x 10⁻¹¹ m³/kg.s²

$g = \dfrac{W}{M}$

$g = \dfrac{389}{75}$

g = 5.187 m/s²

we know,

$g = \dfrac{GM}{r^2}$

$5.19 = \dfrac{GM}{r^2}$ .......(1)

now,

$g' = \dfrac{W}{M}$

$g' = \dfrac{24.31}{75}$

g' = 0.324 m/s²

$g = \dfrac{GM}{(r+h)^2}$

$0.324= \dfrac{GM}{(r+h)^2}$ .........(2)

dividing equation (1)/(2)

$\dfrac{5.19}{0.324}=(\dfrac{(r+h)}{r})^2$

$4=1+\dfrac{h}{r}$

$r = \dfrac{1.86\times 10^4}{3}$

r = 6.2 x 10⁶ m

mass of planet X

from equation 1

$M = \dfrac{g.r^2}{G}$

$M = \dfrac{5.19 \times (6.2\times 10^6)^2}{6.2 \times 10^{-11}}$

M = 3.21 x 10²⁴ kg

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3 years ago