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wolverine [178]
1 year ago
6

An automobile factory is assembling cars and they need to have all of the parts in stock at the assembly line. each car needs fo

ur tires and a spare tire for the trunk. if they produce c cars per day, what formula shows how to calculate the number of tires, t, needed? a. c = 4 t 1 c. t = 4 c 1 b. t = c 4 d. t = 5 c
Mathematics
1 answer:
ELEN [110]1 year ago
7 0

The formula which shows how to calculate the number of tires, t, needed if they produce c cars per day is t = 5c. option D

<h3>Equation</h3>

  • Number of tires needed by each car = 4
  • Number of spare tires needed by each car = 1

Total tires needed by each car = 4 + 1

= 5

  • Number of cars produced per day = c

Total number of tires, t needed for c cars.

Number of tires needed, t = Total tires needed by each car × Number of cars produced per day

t = 5 × c

t = 5c

For instance,

if 5 cars are produced per day

Number of tires needed, t = Total tires needed by each car × Number of cars produced per day

t = 5c

= 5 × 5

t = 25 tires

Therefore, the formula which shows how to calculate the number of tires, t, needed if they produce c cars per day is t = 5c. option D

Learn more about equation:

brainly.com/question/2972832

#SPJ1

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8 0
2 years ago
Daniel invests $2,037 in a retirement account with a fixed annual interest rate of 6% compounded 6 times per year. What will the
notka56 [123]

Answer:

\$5294.72

Step-by-step explanation:

GIVEN: Daniel invests \$2,037 in a retirement account with a fixed annual interest rate of 6\% compounded 6 times per year.

TO FIND: What will the account balance be after 16 years

SOLUTION:

Amount invested by Daniel =\$2037

Annual interest rate =6\%      

Total amount generated by compound interest is  =P(1+\frac{r}{n})^n^t

Here Principle amount P=\$2037

rate of interest r=6\%

number of times compounding done in a year n=6

total duration of time nt=16\text{ years}

putting values we get

=2037(1+\frac{6}{6\times100})^1^6

=2037(\frac{101}{100})^1^6

=\$5294.72

Hence the total balance after 16\text{ years} will be \$5294.72

4 0
2 years ago
en una casa construida con madera el tejado se sostiene con una estructura triangular en el que se utilizan ángulos complementar
professor190 [17]

Answer:

Si me dieras una imagen con esto, podría responderla fácilmente, pero no hay una imagen o modelo para ayudar a disculparme.

Step-by-step explanation:

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6 0
2 years ago
PLEASE HELP ASAP!!
Arada [10]
This is like the equivalent to a jar with 4 green balls and 6 white balls, where you are picking 3. (The 4 green balls signify the friends from kindergarten.) 

You want to solve the probability that the first two balls are green and the third is white. 
First draw --> 4 green out of 10 balls --> 4/10 = 2/5 

Second draw --> 3 green out of 9 balls --> 3/9 = 1/3 

Third draw --> 6 white out of 8 balls --> 6/8 = 3/4 


2/5 x 1/3 x 3/4 

= 6/60 

= 1/10 


so the answer is 1/10 (or 10%)
6 0
2 years ago
Read 2 more answers
Implicit diffrention problems I am really stuck on
AysviL [449]

Answer:

\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

x^4 + x^3y = 5xy^2 -y^3

now differentiating in terms of x (\frac{dy}{dx})

4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )

isolating dy/dx to one side

4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )

4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)

\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}

5 0
3 years ago
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