The density of sucrose is 1.58 g/ cm³
<em><u>Calculation</u></em>
Step 1 : calculate the volume of benzene
volume = mass/density
mass of benzene = total mass - mass of sucrose
=17.33 g - 9.35 g =7.98 g
volume = 7.98 / 0.879 =9.08 cm³
Step 2: calculate the volume of sucrose
volume of sucrose= Total volume - volume of benzene
Total volume = 15 ml =15 cm³
volume of sucrose is therefore = 15 cm³ - 9.08 cm³=5.92 cm³
Step 4: calculate the density of sucrose
density = mass/volume
= 9.35 g / 5.92 cm³ = 1.58 g/cm³
Answer:
52.99 kPa
Explanation:
Initial volume V1 = 2.7 L
Initial Pressure P1 = 78.5 kPa
Final Volume V2 = 4.0L
Final Pressure P2 = ?
Temperature is constant
The relationship between these quantities is given by the mathematical expression of Boyles law. This is given as;
V1P1 = V2P2
P2 = V1P1 / V2
P2 = 2.7 * 78.5 / 4.0
P2 = 52.99 kPa
If we are talking about a lower concentration of solutes then the term would be Hypotonic solution.
Answer:
Price ceiling. In order to limit the shortages that naturally result from a price ceiling, the government can do what to certain goods? Ration.
Explanation:
Answer:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Explanation:
From the question given above,
Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
Thus, we can balance the above equation as follow:
Cu(NO3)2 + Al —> Al(NO3)3 + Cu
There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu
There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:
3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:
3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu
Thus, the equation is balanced.