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2 years ago

A)

Chemistry

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

A formula unit of the nitrate salt of Q is Q(NO3)2.

<h3>What is IUPAC nomenclature?</h3>

The IUPAC nomenclature was put together by the international Union of Pure and applied chemistry in order to have a uniform way of naming compounds.

We shall now find the names of the compounds;

1) Na* and HPO4²- ; sodium hydrogen tetraoxophoshate V

2) Potassium cation and cyanide anion ; Potassium cyanide

3) Calcium cation and hypochlorite anion; Calcium oxochlorate I

Knowing that the valency of NO3^- is one and that the compound formed between Q and CO3²- has the formula QCO3 we can conclude that a formula unit of its nitrate salt is Q(NO3)2.

Learn more about IUPAC nomenclature:brainly.com/question/14379357

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Hi, There!

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<h2>Question</h2>

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<h2>Answer</h2>

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<h2>Below is some More Information</h2>

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What mass of KCl will produce a saturated solution in 500.0 g of water at 20°C? The solubility of KCl at 20°C is 34.0 g/100 g H2

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</u>:)

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3 years ago

Read 2 more answers

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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3 years ago