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prohojiy [21]
3 years ago
9

Write a complete electron configuration for borin

Chemistry
1 answer:
olga2289 [7]3 years ago
6 0

The electron configuration for Boron (B) is given as 1s^2 2s^2 2p^1 or [He] 2s^2 2p^1

Answer:

Boron (B) has an atomic number equal to 5 and is an element from Group 13 of the periodic table. It has a total of 5 electrons of which 3 are valence electrons.

The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be 1s^2 2s^2 2p^1

Since 1s^2 is the electron configuration for Helium, Electron configuration for Boron can also be written as [He] 2s^2 2p^1

<em>(Refer attached figure)</em>

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Class material don't interact please
bagirrra123 [75]

A 0.00143 M  concentration of MnO4^- is not a reasonable solution .

<h3>Number of moles of carbonate</h3>

The ions left in solution are Na^+ and NO3^-

Number of moles of calcium nitrate  = 100/1000 L × 1 = 0.1 moles

Since;

1 mole of sodium carbonate reacts with 1 mole of calcium nitrate  then 0.1 moles of sodium carbonate were used.

<h3>Conductivity of filtrate</h3>

The claim of the student that the concentration of sodium carbonate is too low is wrong because the value was calculated from concentration  and volume of calcium nitrate  and not using the precipitate. If the filtrate is tested for conductivity, it will be found to conduct electricity because it contains sodium and NO3 ions.

2) In the reaction as shown, the MnO4^- ion was reduced.

The initial volume is 3.4 mL while the final volume is 29.6 mL.

Number of moles of MnO4^- ion = (29.6 mL - 3.4 mL)/1000 × 0.0235 M = 0.0006157 moles

<h3>The calculations are performed as follows</h3>

  • If 2 moles of MnO4^- reacted with 5 moles of acid

0.0006157 moles of MnO4^- reacted with  0.0006157 moles ×  5 moles/ 2 moles

= 0.0015 moles

  • In this case, number of moles of acid = 0.139 g/90 g/mol = 0.0015 moles

Number of moles of MnO4^-  = 0.00143 M × (29.6 mL - 3.4 mL)/1000

= 0.000037 moles

  • If 2 moles of MnO4^- reacts with 5 moles of acid

0.000037 moles of MnO4^- reacts with 0.000037 moles × 5 moles/ 2 moles

= 0.000093 moles

  • Hence, this is not a reasonable amount of solution.

Learn more about MnO4^- : brainly.com/question/10887629

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What is the melting point of gallium?
Alenkinab [10]
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Given the following reaction: NH4SH (s) &lt;--&gt; NH3 (g) + H2S (g) If we start
almond37 [142]

Answer:

D. 0.3 M

Explanation:

                                              NH4SH (s)      <-->            NH3 (g) + H2S (g)

Initial concentration              0.085mol/0.25L             0                 0

Change in concentration     -0.2M                               +0.2 M        +0.2M

Equilibrium               0.035mol/0.25 L=0.14M             0.2M           0.2M

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