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3 years ago

Write a complete electron configuration for borin

Chemistry

1 answer:

olga2289 [7]3 years ago

6 0

The electron configuration for Boron (B) is given as $1s^2 2s^2 2p^1$ or $[He] 2s^2 2p^1$

Answer:

Boron (B) has an atomic number equal to 5 and is an element from Group 13 of the periodic table. It has a total of 5 electrons of which 3 are valence electrons.

The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be $1s^2 2s^2 2p^1$

Since $1s^2$ is the electron configuration for Helium, Electron configuration for Boron can also be written as $[He] 2s^2 2p^1$

<em>(Refer attached figure)</em>

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4 years ago

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3 years ago

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Consider the following chemical equilibrium: 4NH3+3O2=2N2+6H2O Now write an equation below that shows how to calculate from for

erma4kov [3.2K]

This is an incomplete question, here is a complete question.

Consider the following chemical equilibrium:

$4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)$

Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Answer :

The expression of $K_c$ will be,

$K_c=\frac{[N_2]^2[H_2O]^6}{[NH_3]^4[O_2]^3}$

The expression of $K_p$ will be,

$K_p=K_c(RT)$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)$

The expression of $K_c$ will be,

$K_c=\frac{[N_2]^2[H_2O]^6}{[NH_3]^4[O_2]^3}$

The relation between $K_p$ and $K_c$ is:

$K_p=K_c(RT)^{\Delta n}$

Form the above reaction we conclude that:

$\Delta n=n_{product}-n_{reactant}$

$\Delta n=(6+2)-(4+3)$

$\Delta n=1$

The expression of $K_p$ will be,

$K_p=K_c(RT)^{1}$

$K_p=K_c(RT)$

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3 years ago

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3 years ago

36. Dimensional Analysis: A useful way to convert units using multiplication & division *Always start with what you are give

ollegr [7]

Answer:

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Explanation:

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