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prohojiy [21]
3 years ago
9

Write a complete electron configuration for borin

Chemistry
1 answer:
olga2289 [7]3 years ago
6 0

The electron configuration for Boron (B) is given as 1s^2 2s^2 2p^1 or [He] 2s^2 2p^1

Answer:

Boron (B) has an atomic number equal to 5 and is an element from Group 13 of the periodic table. It has a total of 5 electrons of which 3 are valence electrons.

The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be 1s^2 2s^2 2p^1

Since 1s^2 is the electron configuration for Helium, Electron configuration for Boron can also be written as [He] 2s^2 2p^1

<em>(Refer attached figure)</em>

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3 years ago
A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical
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2 years ago
Which of the following is true?
Tomtit [17]

Answer:

a. A reaction in which the entropy of the system increases can be spontaneous only if it is endothermic.

Explanation:

The change in free energy (ΔG) that is, the <u>energy available to do work</u>, of a system for a constant-temperature process is:

ΔG = ΔH - TΔS

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  • When ΔG > 0 the reaction is nonspontaneous. The reaction is

spontaneous in the opposite direction.

  • When ΔG = 0 the system is at equilibrium.

If <u>both ΔH and ΔS are positive</u>, then ΔG will be negative only when the TΔS  term is greater in magnitude than ΔH. This condition is met when T is large.

3 0
3 years ago
A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
8_murik_8 [283]

Answer: The molecular formula will be C_6O_3H_{12}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

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Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3

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5 0
3 years ago
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