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I'm in the car now so can't lookup periodic table. But you find molecular weight of: 1 Ca + 2 Cl
Then that
Answer:
The minimum concentration of Cl⁻ that produces precipitation is 12.6M
Explanation:
The Ksp of PbCl₂ is expressed as:
PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq)
The Ksp is:
Ksp = 1.6 = [Pb²⁺] [Cl⁻]²
When Ksp = [Pb²⁺] [Cl⁻]² the solution begind precipiration.
A 0.010M Pb(NO₃)₂ is 0.010M Pb²⁺, thus:
1.6 = [0.010M] [Cl⁻]²
160 = [Cl⁻]²
12.6M = [Cl⁻]
<h3>The minimum concentration of Cl⁻ that produces precipitation is 12.6M</h3>
1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.
d(H) = 10 nm; diameter of hydrogen atom.
d(H) = 10 nm · 0.001 µm/nm.
d(H) = 0.01 µm = 10⁻² µm.
2) 1 nm = 10⁻⁹ m
; one meter is equal to 0.0000000001 (10⁻⁹) meter.
d(H) = 10 nm.
d(H) = 10 nm · 10⁻⁹ m/nm.
d(H) = 0.00000001 m = 10⁻⁸ m.
3) 1 nm = 10⁻⁶ mm
; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.
d(H) = 10 nm · 10⁻⁶ mm/nm.
d(H) = 0.00001 mm = 10⁻⁵ mm.
Answer:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
The function of HCl is oxidize the gold.
Explanation:
It is possible to balance the reaction seeing each compound as a variable and take an equation for each atom, thus:
Au(s) + HNO₃(aq) + HCl(aq) → HAuCl₄(aq) + NO₂(g) + H₂O(l)
a + b + c = d + e + f
Au: a = d <em>(1)</em>
H: b + c = d + 2f <em>(2)</em>
N: b = e <em>(3)</em>
O: 3b = 2e + f <em>(4)</em>
Cl = c = 4d <em>(5)</em>
Assuming <em><u>a = 1</u></em>:
<em><u>1 = d</u></em> <em>(1)</em>
<u><em>c = 4</em></u> <em>(5)</em>
b + 3 = 2f <em>(2)</em>
3b = 2e + f <em>(4)</em>
As b = e:
b = f <em>(4)</em>
<em><u>f = 3</u></em>; <em><u>b = 3</u></em>; <em><u>e = 3</u></em>
Thus, balanced reaction is:
1Au(s) + 3HNO₃(aq) + 4HCl(aq) → 1HAuCl₄(aq) + 3NO₂(g) + 3H₂O(l)
<em>The function of HCl is oxidize the gold</em> that before reaction is Au⁰ and afte ris Au⁺³
I hope it helps!
