Isotopes are composed of the same atoms but are arranged differently
Answer:
2.87 gram
N2 is the limiting agent
Explanation:
We will find out if there is sufficient N2 and h2 to produce NH3
a) For 2.36 grams of N2
Molar mass of N2 = 28.02
Number of moles of N2 in 2.36 grams = 2.36/28.02
Mass of NH3 = 17.034 g
Now NH3 produced form 2.36 grams of N2 =
2.36/28.02 * 2 * 17.034 = 2.87 g NH3
b) For 1.52 g of H2
NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56
N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.
N2 is the limiting agent as it has smaller product mass
For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
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Answer: 
Explanation:
where,
= boiling point of solution = ?
= boiling point of solvent (X) = 
= freezing point constant = 
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte like urea)
= mass of solute (urea) = 29.82 g
= mass of solvent (X) = 500.0 g
= molar mass of solute (urea) = 60 g/mol
Now put all the given values in the above formula, we get:
Therefore, the freezing point of solution is 
