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1 year ago

Deuterium is a relatively uncommon form of hydrogen, but can be created from what common source?.

Chemistry

1 answer:

Elena-2011 [213]1 year ago

8 0

Deuterium is a relatively uncommon form of hydrogen, but can be created from water.

Heavy hydrogen commonly known as deuterium
stable isotopes of hydrogen
gets its name from the Greek word deuterons means second.
has only one proton and one neutron
nucleus of the hydrogen's deuterium atom is known as a deuteron containing one proton and one neutron.
Deuterium forms chemical bonds that are stronger than regular hydrogen
gas deuterium is colorless
Deuterated water is used in Magnetic Resonance Spectroscopy.
used in the determination of the isotopologue of various organic compounds.
used in Infrared Spectroscopy.

To know more about Deuterium visit : brainly.com/question/27870183

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Write the balanced reaction using the fewest whole number coefficients to describe the reaction between gaseous hydrogen and gas

Anastasy [175]

Answer: The percentage yield of water is 9.5 %

Explanation:

We are given:

Moles of hydrogen = 14 moles

Moles of oxygen = 10 moles

The chemical equation for the formation of water from hydrogen and oxygen follows:

$2H_2+O_2\rightarrow 2H_2O$

By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas

So, 14 moles of hydrogen gas will react with = $\frac{1}{2}\times 14=7mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrogen gas produces 2 moles of water

So, 14 moles of hydrogen gas will produce = $\frac{1}{2}\times 14=7mol$ of water

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 1.33 moles

Theoretical yield of water = 14 moles

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{1.33mol}{14mol}\times 100\\\\\% \text{yield of water}=9.5\%$

Hence, the percent yield of the water is 9.5 %.

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2 years ago

For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.

vichka [17]

Answer:

$\Delta G =-103.95kJ$

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

$\Delta G =\Delta H-T\Delta S$

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

$\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ$

Best regards!

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Explanation:

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