Answer:15,883.63 KJ
Explanation:
Given
Power=400 W
Freezing compartment temperature is 273 K
Outside air Temperature=306 K
Time =80 minutes
Energy Required to deliver 400 w power in 80 minutes
E=1920 KJ
and we know COP of refrigerator is given by




Therefore 15,883.63 KJ is removed in 80 minutes
Answer:
<em>The answer is B) water to air</em>
Answer:48.52 kJ
Explanation:
Given
Resistance
temperature increases from
Voltage=50 V
Heat given(H)
Where V=voltage applied
t=time
R=Resistance

Heat absorbed by water is

where
m=mass of water
c=specific heat of water
=change in temperature

Therefore 90-41.48=48.52 kJ is not absorbed by water and leaves the system into the surroundings.
Answer:
7.11x10^-3
Explanation:
We are to get the volume rate of flows
1/2pv1² + pl = 1/2pv2²
Such that A1V1 = A2V2
V1 = A2V2/A1
From the attachment I uploaded, we have a formula named equation 1 from which I have plugged in these values
P2 = 33000
P2 = 24000
P = 1000
r2 = 2.25
r1 = 4
When we put these values into the equation,
V2 = 4.47
A2V2 = pi(0.0225)²x4.47
= 7.7x19^-3m³/s
The force exerted on the box is 56 N
Explanation:
The work done by a force on an object is given by

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the box in this problem, we have:
W = 2240 J is the work done
d = 40 m is the displacement of the box
Assuming that the force is parallel to the displacement, 
Solving the equation for F, we find the force exerted on the box:

Learn more about work:
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brainly.com/question/6443626
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