Answer:
Explanation:
Given that
Radius =r
Electric filed =E
Q=Charge on the ring
The electric filed at distance x given as
For maximum condition
For maximum condition
At the electric field will be maximum.
Q C Many people assume air resistance acting on a moving object will always make the object slow down. It can, however, actually
1 answer:
The most effective forces on the object are the backward force of air resistance relatively very small in magnitude, and the force of gravity. Because the spiral path of the satellite is not perpendicular to the gravitational force, one element of the gravitational force pulls forward. at the satellite to do fantastic work & make its speed increase.
<h3>What is called gravitational force?</h3>Gravity, additionally referred to as gravitation, is a force that exists amongst all material gadgets withinside the universe. For any objects or particles having nonzero mass, the force of gravity tends to draw them in the direction of each other. Gravity operates on objects of all sizes, from subatomic particles to clusters of galaxies.
To learn more about gravitational force, visit;
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Answer:
<h3>The answer is 2.51 s</h3>Explanation:
The time taken can be found by using the formula
d is the distance
v is the velocity
From the question we have
We have the final answer as
<h3>2.51 s</h3>Hope this helps you
Answer:
The third charged particle must be placed at x = 0.458 m = 45.8 cm
Explanation:
To solve this problem we apply Coulomb's law:
Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:
Formula (1)
F: Electric force in Newtons (N)
K : Coulomb constant in N*m²/C²
q₁, q₂: Charges in Coulombs (C)
d: distance between the charges in meters (m)
Equivalence
1μC= 10⁻⁶C
1m = 100 cm
Data
K = 8.99 * 10⁹ N*m²/C²
q₁ = +5.00 μC = +5.00 * 10⁻⁶ C
q₂= +7.00 μC = +7.00 * 10⁻⁶ C
d₁ = x (m)
d₂ = 1-x (m)
Problem development
Look at the attached graphic.
We assume a positive charge q₃ so F₁₃ and F₂₃ are repulsive forces and must be equal so that the net force is zero:
We use formula (1) to calculate the forces F₁₃ and F₂₃
F₁₃ = F₂₃
We eliminate k and q₃ on both sides
We eliminate 10⁻⁶ on both sides
We solve the quadratic equation:
In the option x₂, F₁₃ and F₂₃ will go in the same direction and will not be canceled, therefore we take x₁ as the correct option since at that point the forces are in opposite way .
x = 0.458m = 45.8cm
Answer:
2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.
Explanation:
The chemical reaction between magnesium and oxygen gives magnesium oxide as a product.The reaction is chemically represented as:
Magnesium is a metal of group-2 with 2 valence electrons.It has atomic number of 12.
In order to attain noble gas configuration it will loose two electrons.
...[1]
Oxygen is a non metal of group-16 with 6 valence electrons..It has atomic number of 8.
In order to attain noble gas configuration it will gain two electrons.
..[2]
2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.