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ValentinkaMS [17]
1 year ago
8

Q C Many people assume air resistance acting on a moving object will always make the object slow down. It can, however, actually

be responsible for making the object speed up. Consider a 100 - kg Earth satellite in a circular orbit at an altitude of 200 km . A small force of air resistance makes the satellite drop into a circular orbit with an altitude of 100km. (e) Show that the system has lost mechanical energy and find the amount of the loss due to friction.
Physics
1 answer:
OLga [1]1 year ago
7 0

$E_i-E_f=-17.94 \times 10^9 \mathrm{~J}-\left(-18.30 \times 10^9 \mathrm{~J}\right)=3.60 \times 10^8 \mathrm{~J}$.

The most effective forces on the object are the backward force of air resistance relatively very small in magnitude, and the force of gravity. Because the spiral path of the satellite is not perpendicular to the gravitational force, one element of the gravitational force pulls forward. at the satellite to do fantastic work & make its speed increase.

<h3>What is called gravitational force?</h3>

Gravity, additionally referred to as gravitation, is a force that exists amongst all material gadgets withinside the universe. For any objects or particles having nonzero mass, the force of gravity tends to draw them in the direction of each other. Gravity operates on objects of all sizes, from subatomic particles to clusters of galaxies.

To learn more about gravitational force, visit;

brainly.com/question/9266911

#SPJ4

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One’s behavior cannot be affected by one’s subconscious
igomit [66]

That statement is false

Our subconscious tend to give a strong influence to our behaviours even if we are not feeling it directly.

For example, let's say that there is a boy that hurt by cats and it's ingrained in his head that cats possess high level of danger to him. Even after that boy grow up, his subsconcious would most likely cause a certain level of paranoia that make him either scared of cats or simply annoyed by seeing them.

3 0
3 years ago
Read 2 more answers
Michael Jordan, el célebre basquetbolista, ganó el torneo de clavadas de la NBA en 1988. Para lograr la hazaña saltó 1.35 metros
kozerog [31]

(a) 0.40 s

First of all, let's find the initial speed at which Jordan jumps from the ground.

The maximum height is h = 1.35 m. We can use the following equation:

v^2-u^2=2gh

where

v = 0 is the velocity at the maximum height

u is the initial velocity

g=-9.8 m/s^2 is the acceleration of gravity

Solving for u,

u=\sqrt{-2gh}=\sqrt{-2(-9.8)(1.35)}=5.14 m/s

The time needed to reach the maximum height can now be found by using the equation

v=u+gt

Solving for t,

t=\frac{v-u}{g}=\frac{0-5.14}{-9.8}=0.52s

Now we can find the velocity at which Jordan reaches a point 20 cm below the maximum height, so at a height of

h' = 1.35 - 0.20 = 1.15 m

Using again the equation

v'^2-u^2=2gh'

we find

v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(1.15)}=1.97 m/s

And the corresponding time is

t'=\frac{v'-u}{g}=\frac{1.97-5.14}{-9.8}=0.32s

So the time to go from h' to h is

\Delta t = t-t'=0.52-0.32=0.20 s

And since we have also to take into account the fall down (after Jordan reached the maximum height), which is symmetrical, we have to multiply this time by 2 to get the total time of permanence in the highest 20 cm of motion:

\Delta t=2\cdot 0.20 = 0.40 s

(b) 0.08 s

This part is easier since we need to calculate only the velocity at a height of h' = 0.20 m:

v'^2-u^2=2gh'

v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(0.20)}=4.74 m/s

And the corresponding time is

t'=\frac{v'-u}{g}=\frac{4.74-5.14}{-9.8}=0.04s

So this is the time needed to go from h=0 to h=20 cm; again, we have to take into account the motion downwards, so we have to multiply this by 2:

\Delta t = 2\cdot 0.04 =0.08 s

8 0
3 years ago
If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. Wh
In-s [12.5K]

Answer:

 v = -v₀ / 2

Explanation:

For this exercise let's use kinematics relations.

Let's use the initial conditions to find the acceleration of the electron

            v² = v₀² - 2a y

when the initial velocity is vo it reaches just the negative plate so v = 0

           a = v₀² / 2y

now they tell us that the initial velocity is half

          v’² = v₀’² - 2 a y’

          v₀ ’= v₀ / 2

at the point where turn v = 0              

          0 = v₀² /4  - 2 a y '

          v₀² /4 = 2 (v₀² / 2y)  y’

          y = 4 y'

          y ’= y / 4

We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.

         v² = v₀² -2a y’

         v² = 0 - 2 (v₀² / 2y) y / 4

         v² = -v₀² / 4

         v = -v₀ / 2

We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.

7 0
3 years ago
A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator
cricket20 [7]

Answer:

a)= 98kJ

b)=108kJ

c) = 10kJ

Explanation:

a. The work that is done by gravity on the elevator is:

Work = force * distance  

= mass * gravity * distance

= 1000 * 9.81 * 10  

= 98,000 J

= 98kJ

b)The net force equation in the cable

T - mg = ma

T = m(g+a)

T = 1000(9.8 + 10)

T = 10800N

The work done by the cable is

W = T × d

= 10800N × 10

= 108000

=108kJ

c) PE at 10m = 1000 * 9.81 * 10 = 98,100 J  

Work done by cable = PE +KE  

108,100 J = KE + 98,100 J  

KE = 10,000 J

= 10kJ

=

7 0
3 years ago
Read 2 more answers
calculate the amount of work done by a person while taking a bag of mass 100kg to the top of the building hight 10m. The mass of
vredina [299]

Explanation:

Total mass=100+10=110

Total weight=mass×gravitational field strength

=110×10

=1100N

Work done=force×distance

=1100×10

=11000J

<em>Please mark me as brainliest if this helped you!</em>

6 0
2 years ago
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