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Assoli18 [71]
2 years ago
10

A coil of Nichrome wire is 25.0 m long. The wire has a diameter of 0.400mm and is at 20.0°C. If it carries a current of 0.500 A,

what are (b) the power delivered to it?
Physics
1 answer:
yaroslaw [1]2 years ago
4 0

The power delivered to the coil is 0.5 Watts

<h3>Resistivity of a material</h3>

The formula for calculating the power delivered to it is expressed according to the equation

Power = I²R

where

I is the current

R is the resistance

Given

Current = 0.500A

Determine the resistance using the resistivity formula

R = ρL/A

Substitute the given parameters

R = 10^-6*(25)/0.002²

R = 2ohms

Substitute

Power = I²R

Power = (0.5)²(2)

Power = 0.5watts

Hence the power delivered to the coil is 0.5 Watts

Learn more on resistivity here: brainly.com/question/17010736

#SPJ4

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Complete Question:

A hollow cylinder with an inner radius of 4.0mm and an outer radius of 30mm conducts a 3.0-A current flowing parallel to the axis of the cylinder. If the current density is uniform throughout the wire, what is the magnitude of the magnetic field at a point 12mm from its center?

Answer:

The magnitude of the magnetic field = 7.24 μT

Explanation:

Inner radius, a = 4.0 mm = 0.004 m

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d² = 0.012² - 0.004²

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The magnitude of the magnetic field is given by:

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