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chubhunter [2.5K]
2 years ago
10

47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a

Physics
1 answer:
butalik [34]2 years ago
7 0

Answer:

kinetic

Explanation:

kinetic energy is powered by motion or gravity the steeper the hill is the faster a ball will roll

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PE (potential energy) + KE (kinetic energy) will equal ME (mechanical energy) ... explain this in your own words, or by using an
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Answer:

Potential energy plus kinetic energy equals mechanical energy because mechanical energy is basically just all of an object's energy, it's just two kinds of energy. The potential is stored inside and kinetic is being used. Both of those together is the total amount of the objects energy, which is the mechanical energy.

Explanation:

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A body is at aheight of 81m and is ascending upwards with a velocity of 12m/s .a body of 2 kg weight is dropped from it.if g=10m
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First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
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Two engines create SIL values of 75 dB and 85 dB respectively. What dB reading would you expect when both are run simultaneously
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An object is dropped from the top of a building and is observed to take 7. 2s to hit the ground. How tall is the building?.
maw [93]

the height of the building is H=36 m.

<h3>What is The Law of Gravity?</h3>

According to Newton's law of gravity, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.

Properties of Gravity -

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Examples of Gravity -

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v₀=0 m/s

H₀=0 m

g=10 m/s²

t=7,2 s

H - ?

H= H_{0} + v_{0}t+\frac{gt^{2} }{2}   \\

H = 0 +0 × 7.2 + 10(7.2)²/2

H = 36m

to learn more about Gravity go to - brainly.com/question/12528243

#SPJ4

8 0
1 year ago
A rifle bullet with mass 8.00g strikes and embeds itself in a block with mass 0.992kg that rests on a frictionless, horizontal s
mafiozo [28]

Answer:

block velocity   v = 0.09186 = 9.18 10⁻² m/s  and speed bollet   v₀ = 11.5 m / s

Explanation:

We will solve this problem using the concepts of the moment, let's try a system formed by the two bodies, the bullet and the block; In this system all scaffolds during the crash are internal, consequently, the moment is preserved.

Let's write the moment in two moments before the crash and after the crash, let's call the mass of the bullet (m) and the mass of the Block (M)

Before the crash

     p₀ = m v₀ + 0

After the crash

   p_{f} = (m + M) v

    p₀ = p_{f}

    m v₀ = (m + M) v                    (1)

Now let's lock after the two bodies are joined, in this case the mechanical energy is conserved, write it in two moments after the crash and when you have the maximum compression of the spring

Initial

    Em₀ = K = ½ m v2

Final

    E m_{f}= Ke = ½ k x2

   Emo = E m_{f}

   ½ m v² = ½ k x²

   v² = k/m  x²

Let's look for the spring constant (k), with Hook's law

   F = -k x

   k = -F / x

   k = - 0.75 / -0.25

   k = 3 N / m

Let's calculate the speed

  v = √(k/m)   x

  v = √ (3/8.00)   0.15

  v = 0.09186 = 9.18 10⁻² m/s

This is the spped of  the  block  plus bullet rsystem right after the crash

We substitute calculate in equation  (1)

   m v₀ = (m + M) v

  v₀ = v (m + M) / m

  v₀ = 0.09186 (0.008 + 0.992) /0.008

  v₀ = 11.5 m / s

6 0
2 years ago
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