A jet airplane flying from Darwin, Australia, has an air speed of 260 m/s in a direction 5.0º south of west. It is in the jet st
1 answer:
Answer:
Vj,g = - 224.19 i - 31.72 j
magnitude of velocity = 226.42 m/s
Explanation:
Velocity of jet with respect to air = 260 m/s in 5 degree South of west
Velocity of air with respect to ground = 35 m/s in 15 degree south of east
Write these velocities in vector form
Vj,a = 260 (- Cos 5 i - Sin 5 j) = - 259 i - 22.66 j
Va,g = 35 ( Cos 15 i - Sin 15 j) = 33.81 i - 9.06 j
Velocity of jet with respect to air = velocity of jet with respect to ground -
velocity of air with respect to ground
Vj,a = Vj,g - Va,g
Vj,g = Vj,a + Va,g
Vj,g = - 259 i - 22.66 j + 33.81 i - 9.06 j
Vj,g = - 224.19 i - 31.72 j
The magnitude of velocity of jet relative to ground or earth is
=
= 226.42 m/s
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