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1 year ago

What is 1/300000 as a decimal?

Mathematics

1 answer:

olasank [31]1 year ago

6 0

Answer:

divide numerator by the denominator of the fraction.Mean you can divide it

Step-by-step explanation:

I am not sure my answer correct or not,hope you know it.

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Solve:::::::::::::::: <img src="https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%203%28y%20%2B%203%29%20-%2010%20%3D%202y%20%2B%201"

Nataly_w [17]

$\sf{\pmb{ANSWER : }}$

let the equation be

$\sf \: 3(y + 3) - 10 = 2y + 1$

$\sf \: 3y + 9 - 10 = 2y + 1$

$\sf \: 3y - 1 = 2y + 1$

$\sf \: 3y -2y = 1 + 1$

$\purple {{{\sf y = 2 }}}$

https://brainly.in/app/profile/18799022

6 0

3 years ago

Read 2 more answers

Solve y=3/2 plzzzzzzzzzzzzzzzzzzzzzzzzzz help

FromTheMoon [43]

Go to 1.5 on the y axis. Then make a horizontal line that stays on that elevation from 1.5

8 0

3 years ago

Find the solution set for this equation.

LuckyWell [14K]

Answer:

m = -5, 0

Step-by-step explanation:

Easiest and quickest way to do this is to graph the equation and find where it intersects the x-axis. If not, then use completing the square or quadratic formula to find your roots.

6 0

3 years ago

Look at the graph below and answer the following.

bearhunter [10]

Answer:

Part 1) The graph has three (3) x-intercepts and has one (1) y-intercept

Part 2) The y-value of the minimum point is -3

Part 3) f(4)=3

Part 4) f(0)=3

Part 5) f(5)=1.5

Part 6) x=-6

Part 7) The horizontal line y=-1 intersects the graph three times

Part 8) The value of the function for f(6) is equal to zero

Part 9) The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) The function is positive on the interval (-3,6) and (10,11) and is negative on the interval (-6,-3) and (6,10)

Step-by-step explanation:

Part 1) Find the number of x-intercepts and y-intercepts of the graph

we know that

The x-intercepts are the values of x when the value of y (the function) is equal to zero

Look at the graph

The graph has 3 x-intercepts

The x-intercepts are the points (-3,0), (6,0) and (10,0)

The y-intercepts are the values of y when the value of x is equal to zero

Look at the graph

The graph has 1 y-intercept

The y-intercept is the point (0,3)

Part 2) The y value of the minimum point on the graph is?

we know that

Look at the picture

The minimum point is (-6,-3)

therefore

The y-value of the minimum point is -3

Part 3) f(4) is equal to?

we know that

f(4) is the value of the function when the value of x is equal to 4

Look at the graph

For x=4

The value of the function is equal to y=3

therefore

f(4)=3

Part 4) f(0) is equal to?

we know that

f(0) is the value of the function when the value of x is equal to 0

Look at the graph

For x=0

The value of the function is equal to y=3

therefore

f(0)=3

Part 5) f(5) is equal to?

we know that

f(5) is the value of the function when the value of x is equal to 5

Look at the graph

For x=5

The value of the function is about y=1.5 (see the attached figure)

therefore

f(5)=1.5

Part 6) The value of x when f(x)= -3 is?

Look at the graph

we have the point (-6,-3)

when the value of f(x)=-3

the value of x is equal to x=-6

Part 7) The horizontal line y = -1 intersects the graph _____ times?

Look at the graph

The horizontal line y=-1 intersects the graph three times (see the attached figure)

Part 8) f(6) is positive or negative?

Look at the graph

we have the point (6,0)

For x=6

The value of the function is equal to zero

Part 9) Is the graph increasing or decreasing on the interval -6?

Look at the graph

The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) Is the graph positive or negative on the interval 6

Look at the graph

The function is positive (f(x) > 0) on the interval (-3,6) and (10,11) and is negative (f(x) < 0) on the interval (-6,-3) and (6,10)

4 0

3 years ago

A profit of a football club after a takeover is modeled by p(t) = t3 - 14t2 + 20t + 120, which t is the number of years after th

Bogdan [553]

T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120

Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10

Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)

0 = 3t - 2
2 = 3t
2/3 = t

Plug 2/3 into original equation, this is a maximum. We want the minimum:

0 = t - 5
5 = t

Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5

6 0

3 years ago