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Mice21 [21]
1 year ago
9

This image was produced by a comouter it shoes conplext molecule consisting of many atoms

Chemistry
1 answer:
VashaNatasha [74]1 year ago
4 0

Answer:

using a computer wont be as messy

Explanation:

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What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution?
trapecia [35]

molarity of a solution means mols per liter.

First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.

Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.

Finally, divide the mols over solution to get .787M

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3 years ago
What is the total volume of solution that was dispensed from this burette? before <br><br> after
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Chemicals used in a laboratory investigation must be safely discarded. Which method is the safest way to dispose of chemicals at
Tema [17]

Answer:

Disposing of the discarded chemicals can be done by certain sfae methods mention as follows:

Explanation:

Most of the chemical wastes are dispose through the EHS waste program. Organic chemicals and solvents that can not be drain should be closed in a tight fitted container that has label on it as Hazardous waste, including strong acid and corrosive liquids.

Recycling of these chemicals and incineration is also use for the industrial chemical waste under professional guidance. Incineration is the process of burning chemicals in to ash through high thermal burning.

7 0
3 years ago
What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0
3 years ago
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