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Mice21 [21]
1 year ago
9

This image was produced by a comouter it shoes conplext molecule consisting of many atoms

Chemistry
1 answer:
VashaNatasha [74]1 year ago
4 0

Answer:

using a computer wont be as messy

Explanation:

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A physician has ordered 0.50 mg of atropine, intramuscularly. If atropine were available as 0.25 mg/mL of solution, how many mil
sladkih [1.3K]
If 0.25mg of atropine is in 1mL
                  so
    0.50mg of atropine is in x

x=\frac{0.5mg*1mL}{0.25mg}=2mL
6 0
3 years ago
Which of the following is true for the equilibrium constant of a reaction? (5 pc
Slav-nsk [51]

The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.

Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.

Therefore, option C. equilibrium constant is represented by K is true.

Learn more about the equilibrium constant here:

brainly.com/question/12429748

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8 0
2 years ago
Food is heated up in a microwave. The heat transfer used in a microwave is
azamat
Radiation 

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6 0
2 years ago
Read 2 more answers
During a storm, a tree fell over into a river. What might happen to this tree?
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6 0
2 years ago
Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu
stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = e^{-2.54738}

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = 5.61*10^-^5

6 0
3 years ago
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