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The reaction of equal molar amounts of benzene, C6H6, and chlorine, Cl2, carried out under special conditions, yields a gas and

WINSTONCH [101]

Answer : The molecular formula of a compound is, $C_6H_5Cl_1$

Solution : Given,

Mass of C = 64.03 g

Mass of H = 4.48 g

Mass of Cl = 31.49 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of Cl = 35.5 g/mole

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{64.03g}{12g/mole}=5.34moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.48g}{1g/mole}=4.48moles$

Moles of Cl = $\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{31.49g}{35.5g/mole}=0.887moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.34}{0.887}=6.02\approx 6$

For H = $\frac{4.48}{0.887}=5.05\approx 5$

For Cl = $\frac{0.887}{0.887}=1$

The ratio of C : H : Cl = 6 : 5 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $C_6H_5Cl_1$

The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{112.5}{112.5}=1$

Molecular formula = $(C_6H_5Cl_1)_n=(C_6H_5Cl_1)_1=C_6H_5Cl_1$

Therefore, the molecular of the compound is, $C_6H_5Cl_1$

5 0

3 years ago

(08.02

bogdanovich [222]

Answer:

b. The molarity of the solution increases

Explanation:

The correct answer is option b, that is the molarity of the solution increases.

Because the molarity is the concentration of the solution and it is explained as the amount of solute in amount of solution.

Solution: is the solute dissolved in solvent.

So if we increases the amount of solute in solvent the concentration in terms of molarity of solution increases and if we increase amount of solvent or water then the concentration or molarity increases.

Suppose we have form a sugar solution of 1 L by adding 4 mole of sugar then what happen

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 4/ 1 L of solution = 4 M

So the molarity of solution is 4 now if we add 2 mole more sugar to the same amount of sugar and amount of solution remain the same

now the no. of moles of sugar = 6 mole

So,

Use the Molarity formula

Molarity = no. of moles / 1 L of solution

put values in the formula

Molarity = 6 mol / 1 L of solution = 6 M

So the correct option is b.

7 0

3 years ago

After three half-lives of an isotope, 1 billion (⅛) of the original isotope’s atoms still remain in a certain amount of this ele

erica [24]

You would expect 500 million atoms to be present. When a source experiences a half-life, it is a point in which atoms have degraded to half what they used to be in mass. 1/2(1 billion) = 500 million

Brainliest answer please

4 0

3 years ago

My friend and her family had dinner at a restaurant. The total bill was $74. They want to leave a 15% tip for the wait staff. Ho

vladimir1956 [14]

$74 +15% (11.10) = $85.50 is you Answer

8 0

3 years ago

Which chemical equation shows that the total mass during a chemical reaction stays the same?

Nataliya [291]

All chemical equations show that the total mass of the reaction stays the same.

4 0

3 years ago