If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w
ill be recovered
1 answer:
Answer:
25.0 g.
Explanation:
- From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.
- <em>So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.</em>
- <em>Thus, the grams of the dry salt that will be recovered is 25.0 g.</em>
You might be interested in