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3 years ago

7

If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w

ill be recovered

1 answer:

balu736 [363]3 years ago

5 0

Answer:

25.0 g.

Explanation:

From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.

<em>So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.</em>

<em>Thus, the grams of the dry salt that will be recovered is 25.0 g.</em>

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