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morpeh [17]
3 years ago
10

A plane passes over Point A with a velocity of 8000 m/s north. Forty seconds later it passes over Point B at a velocity of 10,00

0 m/s north. What is the planes’ acceleration from A to B?
Physics
1 answer:
Airida [17]3 years ago
7 0

Answer:

The planes’ acceleration from A to B is 500m/s^2

Explanation:

Given that the initial velocity u is 8000m/s

and also given the final velocity v=10,000 m/s

the time taken to move from A to B = 40 second

The acceleration is defined as the rate of change of velocity with time

we know that the expression for acceleration is given as

a=(v-u)/t

substituting our given data into the expression for a we have

a=(10000-8000)/40

a=2000/40

a=500m/s^2

The planes’ acceleration from A to B is 500m/s^2

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Option (2)

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From the figure attached,

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Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

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Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

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Direction of the resultant will be towards vector A.

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Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

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