Mass= density x volume
1.3 kg/m^3 x ( 2.5x4x10) m^3
= 130 kg
<h3>Answer : </h3><h3 /><h3>A ) The larger gear can be moved by applying a relatively small force on the smaller gear.</h3>
<h3>B )
The force applied on the smaller gear is transmitted without any loss to the larger gear .</h3><h3 /><h3>
C ) the direction of motion can be changed without changing the direction of the applied force .</h3>
D ) the system would continue to move without any further, after and initial force has set in motion.
Answer and Explanation:
The ball is bouncing to a height of 1/3 of its previous height this is a type of geometric sequence the total distance can be found by the sum of geometric sequence
For example let the initial height is 243 fit
After one bounce it will reach 243/3 =81 feet
After second bounce 81/3=27 feet
After third bounce 27/3 =9 feet
After fourth bounce 9/3 =3 feet
So a sequence is formed that is 243,81,27,9,3..........
Here 
Sum of infinite GP = 
From this formula we can find the total distance traveled by the ball
Answer:
25 seconds
Explanation:
Assuming the woman is accelerating at a constant rate of
from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.
Let she takes t seconds to cover the distance, s=115 m.
As acceleration, 

Now, from the equation of motion


[ from equation (i)]

seconds.
Hence, she takes 25 seconds to walk the distance.
Answer:
32 C > 32 F > 32 K
Explanation:
32 F, 32 C, 32 K
Let T1 = 32 F
T2 = 32 C
T3 = 32 K
Convert all the temperatures in degree C
The relation between F and C is given by
(F - 32) / 9 = C / 100
so, (32 - 32) / 9 = C / 100
C = 0
So, T1 = 32 F = 0 C
The relation between c and K is given by
C = K - 273 = 32 - 273 = - 241
So, T3 = 32 K = - 241 C
So, T 1 = 0 C, T2 = 32 c, T3 = - 241 C
Thus, T2 > T1 > T3
32C > 32 F > 32 K