To find this you know that the A of a square = s^2
So the length of one side equals

Since this is a perfect square, it would equal

And

Also you know it is a perfect square because the first and last terms are perfect squares :) :D
let's firstly convert the mixed fractions to improper fractions and then add, bearing in mind that the LCD from 8 and 4 is simply 8.
![\bf \stackrel{mixed}{5\frac{7}{8}}\implies \cfrac{5\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{47}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{47}{8}+\cfrac{11}{4}\implies \stackrel{\textit{using the LCD of 8}}{\cfrac{(1)47~~-~~(2)11}{8}}\implies \cfrac{47-22}{8}\implies \cfrac{25}{8}\implies 3\frac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B47%7D%7B8%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B47%7D%7B8%7D%2B%5Ccfrac%7B11%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%208%7D%7D%7B%5Ccfrac%7B%281%2947~~-~~%282%2911%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B47-22%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B25%7D%7B8%7D%5Cimplies%203%5Cfrac%7B1%7D%7B8%7D)
1 billion is=1,000,000,000
count the zeros since it has only 10's as the factors
9 zeros
the 10=2 times 5
so there are 10 2's and 10 5's so the prime factorization is
2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 or
2^10 times 5^10
Answer:
c= 39.95 +0.15 (s + r) (take the 63 received and plug it in for r and 53.45 in for c then solve)
53.45= 39.95 +0.15 (s +63) (use the distributive property)
53.45 = 39.95 + 0.15s + 9.45 (combine like terms on the right side)
53.45 = 49.40 +0.15s (subtract 49.40 from both sides)
4.05 = 0.15s (divide both sides by 0.15 so isolate s)
s= 27 (how many text messages were sent)
Step-by-step explanation:
I hope this helps :)
Answer:
100 in is the answer.
Step-by-step explanation:
a = 60 in
b = 80 in
c = ?
According to the Pythagorean theorem,
a² + b² = c²
60² + 80² = c²
3600 + 6400 = c²
c² = 10000
c = 100 in
∴ the distance between the opposite corners of the bed is 100 in