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2 years ago

Use the equation d=m/v. If a rock has a density of 2g/cm^3 and a volume of 8cm^3, what is the mass?

Physics

1 answer:

Ray Of Light [21]2 years ago

8 0

Answer:

The mass is 16 [g]

Explanation:

We have to remember the formula that defines density, which mentions that the density is equal to mass divided by the volume.

$Density = mass / volume\\where:\\density = 2[\frac{g}{cm^{3} } ]\\Volume = 8 [cm^{3}]$

Now we clear the mass:

$mass= density*volume\\mass = 2[\frac{g}{cm^{3} }]*8[cm^{3} ]\\mass = 16 [g]$

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A sound wave has a frequency of 425 Hz. What is the period of this wave

Oduvanchick [21]

Answer: The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

Explanation:

Frequency of the wave = 425 Hertz = $425 sec^{-1}$

$\text{Time period}=\frac{1}{Frequency}$

$\text{Time period}==\frac{1}{425 sec^{-1}}=0.0023 sec$

The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

5 0

2 years ago

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t

Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, $\dfrac{N_s}{N_p}=\dfrac{46}{1}$

Voltage of primary coil, $V_p=120\ V$

Current in the secondary coil, $I_s=1.8\times 10^{-3}\ A$

The power consumed by the air filter is :

$P_s=I_s\times V_s$ ...........(1)

For a transformer, $\dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}$

So, $P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p$

$P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120$

$P_s=9.936\ Watts$

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

Children are sled riding on a hill One little girl pulls her sled back up the hill and does 379.5 joules of work while pulling i

Serggg [28]

Answer:

2.2N

Explanation:

Given parameters:

Work done = 379.5J

Height = 173m

Unknown:

Amount of force exerted on the sled = ?

Solution:

The amount of force she exerted on the sled is the same as her weight.

Work done is the force applied to move a body through a distance.

Work done = mgh

m is the mass

g is the acceleration due to gravity

h is the height

mg = weight;

Work done = weight x h

379.5 = weight x 173

weight = $\frac{379.5}{173}$ = 2.2N

4 0

2 years ago

Two protons are aimed directly toward each other by a cyclotron accelerator with speeds of 1200 km/s , measured relative to the

Radda [10]

Answer:

The maximum electrical force is $2.512\times10^{-2}\ N$ .

Explanation:

Given that,

Speed of cyclotron = 1200 km/s

Initially the two protons are having kinetic energy given by

$\dfrac{1}{2}mv^2=\dfrac{1}{2}mv^2$

When they come to the closest distance the total kinetic energy is converts into potential energy given by

Using conservation of energy

$mv^2=\dfrac{kq^2}{r}$

$r=\dfrac{kq^2}{mv^2}$

Put the value into the formula

$r=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{1.67\times10^{-27}\times(1200\times10^{3})^2}$

$r=9.57\times10^{-14}\ m$

We need to calculate the maximum electrical force

Using formula of force

$F=\dfrac{kq^2}{r^2}$

$F=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{(9.57\times10^{-14})^2}$

$F=2.512\times10^{-2}\ N$

Hence, The maximum electrical force is $2.512\times10^{-2}\ N$ .

8 0

2 years ago

Newtons third lawWhat action-reaction forces are involved when a rocket engine fires? Why doesnt a rocket need air to push on? A

dangina [55]

Answer: action forc roketorce

reaction force is engine fires

4 0

2 years ago