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2 years ago

Use the equation d=m/v. If a rock has a density of 2g/cm^3 and a volume of 8cm^3, what is the mass?

Physics

1 answer:

Ray Of Light [21]2 years ago

8 0

Answer:

The mass is 16 [g]

Explanation:

We have to remember the formula that defines density, which mentions that the density is equal to mass divided by the volume.

$Density = mass / volume\\where:\\density = 2[\frac{g}{cm^{3} } ]\\Volume = 8 [cm^{3}]$

Now we clear the mass:

$mass= density*volume\\mass = 2[\frac{g}{cm^{3} }]*8[cm^{3} ]\\mass = 16 [g]$

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3 years ago

a stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes th

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3 years ago

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3 years ago

A 4.10 g bullet moving at 837 m/s strikes a 820 g wooden block at rest on a frictionless surface. The bullet emerges, traveling

atroni [7]

Answer:

(a) 1.85 m/s

(b) 4.1 m/s

Explanation:

Data

bullet mass, Mb = 4.10 g

initial bullet velocity, Vbi = 837 m/s

wooden block mass, Mw = 820 g

initial wooden block velocity, Vwi = 0 m/s

final bullet velocity, Vbf = 467 m/s

(a) From the conservation of momentum:

Mb*Vbi + Mw*Vwi = Mb*Vbf + Mw*Vwf

Mb*(Vbi - Vbf)/Mw = Vwf

4.1*(837 - 467)/820 = Vwf

Vwf = 1.85 m/s

(b) The speed of the center of mass speed is calculated as follows:

V = Mb/(Mb + Mw) * Vbi

V = 4.1/(4.1 + 820) * 837

V = 4.1 m/s

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3 years ago