Question

when 4.00 g of sulfur are combined with 4.00 g of oxygen, 8.00 g of sulfur dioxide (so2) are formed. what mass of oxygen would be required to convert 4.00 g of sulfur into sulfur trioxide (so3)?

Answer 1

Answer:

6g O2

Explanation:

Mole to mole ratio:

A balanced chemical equation shows a chemical reaction while maintaining the law of conservation of mass. The coefficients of the substances are known to be very helpful in computations as they represent the equivalent amounts of moles of the species that would be participating in the reaction.

We set up the chemical equation and then find the balanced chemical expression.

S+O2→SO3

Balance 

2S+3O2→2SO3

We use the following values for the variables:

mS=4.0 gm

We proceed with the solution.

mO2= 4 g S × 1 mol S/ 32 g S × 3 mol O2/ 2 mol S × 32g O/ 1 mol O2

mO2 = 6 g

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