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Ronch [10]
2 years ago
14

3. Which term is defined as "anything that has mass and occuples space"?

Chemistry
2 answers:
ipn [44]2 years ago
6 0

Answer:

matter

Explanation:

Matter is anything that has mass and occupies space .

nordsb [41]2 years ago
3 0

Answer:

matter

Explanation:

All physical 'stuff'

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One molecule of glucose makes 36 molecules of atp how many molecules of glucose are needed to make 1800 molecules of atp
pogonyaev
You would need exactly 50 molecules of glucose. 
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3 years ago
While waiting for your car to warm up one winter morning, you notice a liquid dripping from your tailpipe. You recently
tangare [24]

Answer:

A

Explanation:

Menthol (M 156.3 g/mol), the strong-smelling substance in many cough drops, is a compound of carbon, hydrogen, and oxygen. When 0.1595 g of menthol was bunted in a combustion apparatus. 0.449 g of CO_2 and 0.184 g of H_2 O formed.

3 0
3 years ago
How many liters of water would it require to 36 grams of the substance?
Bas_tet [7]

3 liters

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3 0
2 years ago
Read 2 more answers
By what quantity must the heat capacity be divided to obtain the specific heat of that material
masha68 [24]
<span>Heat capacity of an object, is the amount of heat energy or thermal energy (unit: Joule) needed to raise the temperature of the object by 1 degree celsius. Unit of heat capacity is J/°C 

Larger object will surely need larger amount of thermal energy to raise its temperature. If you compare 1 litre of water with 0.5 litre of water, the 1L water will have two times the heat capacity. 

It will be more useful to compare specific heat capacity, because then it is the amount of heat energy or thermal energy (unit: Joule) needed to raise the temperature of 1 unit mass of the object by 1 degree celsius. You can then compare between 1 unit mass of water and 1 unit mass of iron. 
Water has higher specific heat capacity than iron, meaning that you need more energy to heat up 1kg of water, then to heat up 1kg of iron. 

The unit will then be J/(kg °C) or J/(g °C).
</span>
6 0
3 years ago
Question
VMariaS [17]

Answer:

12.62 L

Explanation:

First, we have to calculate the moles corresponding to 18.0 g of oxygen gas (MW 32.0).

18.0 g × (1 mol/32.0 g) = 0.563 mol

Then, we can find the volume occupied by 0.563 moles of oxygen at STP (273,15 K, 1.00 atm) using the ideal gas law.

P × V = n × R × T

V = n × R × T / P

V = 0.563 mol × 0.0821 atm.L/mol.K × 273.15 K / 1.00 atm

V = 12.62 L

7 0
3 years ago
Read 2 more answers
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