1 year ago

Never mind, question solved.

Chemistry

1 answer:

Alchen [17]1 year ago

5 0

The answer to the problem is 100

You might be interested in

I recently started a science experiment and need help coming up with a catchy title. Can you help me? Here is my problem stateme

kirill115 [55]

I think Salty Boiling would be a good one lol :)

7 0

3 years ago

Read 2 more answers

PLEASEEEE HELPPP I BEGGGG FOR HELPPP PLEASEE

belka [17]

Answer:

Explanation:

3 0

3 years ago

Read 2 more answers

Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.

Alborosie

Given:

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

To determine:

The Ka of HNO3

Explanation:

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

HNO3 ↔ H+ + NO3-

I 7.50 0 0

C -2.48 +2.48 +2.48

E 5.02 2.48 2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

6 0

3 years ago

Which term names the concentration of salts dissolved in a liquid?

Viefleur [7K]

Hey there!
The answer is D, Salinity.
Salinity is the concentration of salt in water. Ocean water often has high salinity and this can contribute to things like upwelling and water density- but these all start from salinity.
Hope this helps!

4 0

3 years ago

Read 2 more answers

What is the half-life of an isotope that decays to 6.25% of its original activity in 18.9 hours?

inessss [21]

Radioactive material obeys 1st order decay kinetics,
For 1st order reaction, we have
k = $\frac{2.303}{t}Xlog \frac{\text{initial conc.}}{\text{final conc.}}$
where, k = rate constant of reaction

Given: Initial conc. 100, Final conc. = 6.25, t = 18.9 hours

∴ k = $\frac{2.303}{18.9} X log \frac{100}{6.25}$ = 0.1467 hours^(-1)

Now, for 1st order reactions: half life = $\frac{0.693}{k} = \frac{0.693}{0.1467}$ = 4.723 hours.

8 0

3 years ago