Answer: The Kinetic Molecular Theory of Matter
Explanation: The answer is: B. Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.
The Kinetic Molecular Theory of Matter
The attachments dont work, they say that they have been taken down or sum... ?
Answer:
How does non-human life in an urban ecosystem differ from that in an undeveloped forest ecosystem?
Explanation:
In forest eco system the people are uncivilized and not so much educated. And in urban eco system people are intelligent as well as educated this is the main reason. In an urban ecosystem, the only non-human life that live there are the ones that are able to survive under the conditions. However, in undeveloped forest ecosystems, there’s barely any pollution. Therefore, a bigger variety of non-human life is able to live here.
Mark brainliest if you can please :)
Answer:
1x10^–9 M
Explanation:
From the question given,
Concentration of hydronium ion, [H3O+] = 1x10^-5 M.
Concentration of Hydroxide ion, [OH-] =..?
The concentration of the hydroxide ion, [OH-] can be obtained as follow:
[H3O+] x [OH-] = 1x10^–14
1x10^-5 M x [OH-] = 1x10^–14
Divide both side by 1x10^-5
[OH-] = 1x10^–14 / 1x10^-5
[OH-] = 1x10^–9 M
Answer:
0.581 L or 581 mL
Explanation:
As stated in the question, the combined gas law is (P1*V1/T1) = (P2*V2/T2)
Write down the amounts you are given.
V1 = 0.152 L (I was taught to always convert milliliters to liters)
P1 = 717 mmHg
T1 = 315 K
V2 = ?
P2 = 463 mmHg
T2 = 777 K
The variable that is being solved for is final volume. Fill in the combined gas law equation with the corresponding amounts and solve for V2.
(717 mmHg*0.152 L) / (315 K) = (463 mmHg*V2) / (777 K)
0.346 = (463*V2) / (777)
0.346*777 = (463*V2) / (777)*777
268.842 = 463*V2
268.842/463 = (463*V2)/463
V2 = 0.581
Pressure and volume are indirectly proportional. This checks out because the volume increased while pressure decreased. Volume and temperature are directly proportional. This checks out because both volume and temperature increased. This is a good way to check your answers. You can also solve each side of the combined gas law equation to see if they are both the same.
