1s^2 2s^2 2p^6 for the Mg2+ ion.
Answer:
0.04838J
Explanation:
Heat is a form of energy that is transferred from one body to another as the result of a difference in temperature between the bodies , here heat is added to the water as a result of temperature change of 0.364 degreesC
Given:change in temperature=0.364
Mass of water=0.0318g
But we need specific heat capacity of water which is
4.2 J/g°C
Then we can calculate How much heat is added by using below formula
Energy = Mass * specific heat capacity *(change in temperature)
energy =0.0318g* 4.18g*0.364
=0.04838J
Answer: 72.93 litres
Explanation:
Given that:
Volume of gas (V) = ?
Temperature (T) = 24.0°C
Convert 24.0°C to Kelvin by adding 273
(24.0°C + 273 = 297K)
Pressure (P) = 1.003 atm
Number of moles (n) = 3 moles
Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K
1.003 atm•V = 73.15 atm•L
Divide both sides by 1.003 atm
1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm
V = 72.93 L
Thus, the volume of the gas is 72.93 litres
Because there is less of it available.
