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Oksana_A [137]
2 years ago
14

The A string of a violin is a little too tightly stretched. Beats at 4.00 per second are heard when the string is sounded togeth

er with a tuning fork that is oscillating accurately at a concert A (400Hz). What is the period of the violin string oscillations
Physics
1 answer:
Basile [38]2 years ago
3 0

Answer:

T=2.5*10^{-3}s

Explanation:

From the question we are told that:

Beat frequency F_b=4

Frequency F=400Hz

Generally the equation for Frequency of the violin is mathematically given by

 f_v=F_b+F

 f_v=4+400Hz

 f_v=404Hz

Therefore the period of the violin string oscillations is

 T=\frac{1}{f_v}

 T=\frac{1}{404}

 T=2.5*10^{-3}s

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The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c
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To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

E= \frac{kQ}{R^2}

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

Q = \frac{ER^2}{k}

Replacing,

Q = frac{(150)(6.38*10^6)}{8.99*10^9}

Q = 6.79*10^5 C

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

F_w = F_e

mg = \frac{kQq}{R^2}

Replacing,

(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}

Solving for q,

q = -4.056C

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

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F = \frac{(8.99*10^9)(-4.056)^2}{110^2}

F = 1.22*10^7N

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

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3 years ago
I NEED HELP ASAP<br>please please please​
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Answer:

B AND D

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