1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
12

Create a mathematical model for the pressure variation as a function of position and time for a sound wave, given that the wavel

ength of the wave is λ = 0.190 m and the maximum pressure variation is ΔPmax = 0.270 N/m2. Assume the sound wave is sinusoidal. (Assume the speed of sound is 343 m/s. Use the following as necessary: x and t. Assume ΔP is in Pa and x and t are in m and s, respectively. Do not include units in your answer.)
Physics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

The equation of position and time for a sound wave is \Delta p=0.270(33.06 x-11342.40 t).

Explanation:

Given that,

Wavelength = 0.190 m

Maximum pressure \Delta P_{max}= 0.270 N/m^2

We know that,

The function of position and time for a sound wave,

\Delta p=\Delta p_{max}(kx-\omega t)....(I)

We need to calculate the frequency

Using formula of frequency

f=\dfrac{v}{\lambda}

Put the value into the formula

f=\dfrac{343}{0.190}

f=1805.2\ Hz

We need to calculate the angular frequency

Using formula of angular frequency

\omega =2\pi f

Put the value into the formula

\omega=2\pi\times1805.2

\omega=11342.40\ rad/s

We need to calculate the wave number

Using formula of wave number

k = \dfrac{2\pi}{\lambda}

Put the value into the formula

k=\dfrac{2\pi}{0.190}

k=33.06

Now, put the value of k and ω in the equation (I)

\Delta p=0.270(33.06 x-11342.40 t)

Hence, The equation of position and time for a sound wave is \Delta p=0.270(33.06 x-11342.40 t).

You might be interested in
A proton and an electron are released from rest, with only the electrostatic force acting. Which of the following statements mus
lbvjy [14]

Answer:

their electrical potential energy decreases. True, because of the negative sign as the distance decreases, it becomes more negative.

The kinetic energy increases. True, the force is attractive as the distance decreases the force increases, so acceleration and therefore the speed

Explanation:

The only force between the proton and the electron is electric

      Fe = k q1q2 / r2

      Fe = - k e2 / r2

We can see that it is an attractive force (negative sign)

The electric power energy is

       U = k q1 q2 / r

       U = -k e2 / r

 

The kinetic energy is

       K = ½ m v2

With the expressions for each term we can analyze the sentences :

Their electric potential energy increases. False,

their electrical potential energy decreases. True, because of the negative sign as the distance decreases, it becomes more negative.

The kinetic energy increases. True, the force is attractive as the distance decreases the force increases, so acceleration and therefore the speed

Kinetic energy decreases False

The acceleration decreases.  False, as the force increases so does the acceleration

7 0
3 years ago
I don’t know this one I need help
nikdorinn [45]
D
Using the kinetic energy 1/2mv^2 formula
5*10^5 is the answer
4 0
2 years ago
A golfer takes two putts to get his ball into the hole he is on green. The first putt displaces the ball 4.5m east, and the seco
LenaWriter [7]
I think its the one going it at 4.5m

8 0
3 years ago
A charge is moving in a magnetic field that points to the left. What direction can the charge move and experience no magnetic fo
tiny-mole [99]
The answer is left and right. 
4 0
3 years ago
Read 2 more answers
Two cars, one of mass 1400 kg, and the
Vikki [24]

Suppose that, in the x-y plane, the first car is moving to the right so that its velocity is given by the vector

v₁ = (14 m/s) i

and the second car is moving upward so that its velocity vector is

v₂ = (20 m/s) j

Then the total momentum of two cars before their collision is

m₁v₁ + m₂v₂ = (1400 kg) (14 m/s) i + (2300 kg) (20 m/s) j

= (19,600 i + 46,000 j) kg•m/s

Their momentum after the collision is

(1400 kg + 2300 kg) v = (3700 kg) v

where v is the velocity vector of the wreckage.

By conservation of momentum,

(19,600 i + 46,000 j) kg•m/s = (3700 kg) v

Let a and b be the horizontal and vertical components of v, respectively. Then

19,600 kg•m/s = (3700 kg) a   ⇒   a ≈ 5.2973 m/s ≈ 5.3 m/s

46,000 kg•m/s = (3700 kg) b   ⇒   b ≈ 12.4324 m/s ≈ 12 m/s

so that the final speed of the wreckage is

||v|| = √(a² + b²) ≈ 13.5139 m/s ≈ 14 m/s

3 0
3 years ago
Other questions:
  • A 10,000-watt radio station transmits at 535 kHz.
    13·2 answers
  • Richardson pulls a toy 3.0 m across the floor by a string, applying a force of0.50 N. During the first meter, the string is para
    10·1 answer
  • Sharks also swim in waters off the coast of Nova Scotia. When gray seals and harbor seals see sharks nearby, they must swim away
    12·1 answer
  • Confirmation bias can affect our problem-solving abilities. <br> A. True <br> B. False
    7·1 answer
  • Sir William Herschel counted the number of stars in different directions, and getting similar numbers in each direction along th
    12·1 answer
  • What is the definition of force?
    10·1 answer
  • Which rock is made mostly of dark, fine-grained silicate minerals, chiefly plagioclase feldspar and pyroxene, and magnetite?
    5·1 answer
  • Which of the following items could be dated by the use of radiocarbon dating?
    15·2 answers
  • After a storm, a hospital may have to rely on backup generators to power some equipment. Which is the energy conversion provided
    13·1 answer
  • Abid is the hare who runs fast and takes long rest while Gautam runs slow but takes short rest. Abid can run at 5 ms−1 while Gau
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!