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Tanzania [10]
3 years ago
7

a merry go round has a radius of 8 meters makes 2 revolutions every 2.5 minutes. A. express the angular speed of the merry go ar

ound in radians per seconds. B. express the angular speed of the merry go round in rpms. C. what is the linear speed of a child seated 7 meters from the center.
Physics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

a).v=83.77x10^{-3} rad/s

b).v=0.8rpm

c).v=0.5865 m/sec.

Explanation:

Given:

r=8m

v=\frac{2rev}{2.5minutes}

a).

2 rev*\frac{2\pirad}{1rev}=4\pi  rad

t=2.5minutes*\frac{60s}{1minute}=150s

The angular speed in radians per seconds is

v=\frac{4\pi}{150s}=83.77x10^{-3} rad/s

b).

v=\frac{2rev}{2.5minute}rpm

v=0.8rpm

c)

Child's distance per revolution

(pi*2r) = 43.988 metres.  

v=(43.988 x 0.0133333) = 0.5865 m/sec.

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Answer:

"Offgassing"

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3 years ago
A potato is shot out of cylinder at an angle of 17 degrees above the horizontal with an initial speed of 20 m/s. What is its max
madreJ [45]

Answer:

Maximum height, h = 1.74 meters

Explanation:

It is given that,

A potato is shot out of the cylinder. It is a case of projectile motion. The potato makes an angle of 17 degrees above the horizontal.

Initial speed with which the potato is shot out, u = 20 m/s

We have to find the maximum height of the potato. The maximum height of a projectile (h) is given by the following formula as :

h=\dfrac{u^2sin^2\theta}{2g}

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3 years ago
Two containers (A and B) are in thermal contact with an environment at temperature T = 280 K. The two containers are connected b
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Answer:

The maximum amount of work is  W = 1563.289 \ J

Explanation:

From  the question we are told that

   The temperature of the environment is  T = 280\ K

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    Initially the number of moles  is  n = 1.2 \ moles

     The volume of container B is V_B = 3.5 \ m^3

     

At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as

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Now from the Ideal gas law

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So substituting for P_A V_A in the equation above

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Substituting values we have that

            W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]

          W = 1563.289 \ J

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