Question

A chemical engineer determines the mass percent of iron in an ore sample by converting the Fe to Fe²⁺ in acid and then titrating the Fe²⁺ with MnO₄⁻. A 1.1081-g sample was dissolved in acid and then titrated with 39.32 mL of 0.03190 M KMnO4. The balanced equation is
8H⁺(aq) + 5Fe²⁺(aq) + MnO⁻₄(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(l)
Calculate the mass percent of iron in the ore.

Answer 1

The mass percent of iron in the ore is 31.6%

Steps

8H⁺(aq) + 5Fe²⁺(aq) + MnO⁻₄(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(l)

V(MnO4^-)=39,32 mL

c(MnO4^-)=0,0319M

n(MnO4^-)=c*V=1,254308 mmol

n(Fe^{2+})=5*n(MnO4^-)=6,27 mmol

Equation

Fe+2H->Fe^+2 + H2

n(Fe)=n(Fe^{2+} )=6,27 mmol

m(Fe)=n*Ar=350,27mg=0,35027g

mass percent(Fe in ore)=m(Fe)/m(ore)*100

=31,61 percent

The mass percent of iron in the ore is 31.6%

What is the equation for the balance formula?

An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides of the reaction have an equal balance of mass and charge.

An illustration of a balanced equation

For instance, consider about the reaction: O2 (g) + 2Mg(s) = 2MgO (g) Two magnesium and two oxygen atoms are present in this reaction on both the reactant and product sides.

learn more about balanced equation here

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