1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amm1812
3 years ago
9

What adaptation does a wood frog have that enable it to survive in deciduous forest ?

Physics
2 answers:
KATRIN_1 [288]3 years ago
6 0

Answer:

The temperature in deciduous forest can range from -30° C to 30°C with 10°C being an average temperature.

Wood frog has adapted to survive in freezing temperatures during winters. It does so by practicing thawing and freezing in a cyclic or systematic manner.

It helps the frog to accumulate glucose and urea in the body. These substances then act as cryoprotectant that is, they prevent the freezing of the cells or tissues (by lowering the freezing point) of the organism and thus prevent the loss of water from the cells.

On arrival of spring, the warm temperature thaws the frog after which the leftover glucose is converted back to glycogen and urea is excreted out of the body.

sweet [91]3 years ago
5 0

Wood frogs have this adaptation where they accumulate urea in their bodies and convert their liver glycogen to glucose to act as cryoprotectants. This prevents the formation of ice crystals in their bodies that could cause damage cells during freezing in winter.  

You might be interested in
about how much more energy is released in a 6.5 richter magnitude earthquake than in one with magnitude 5.5?
OverLord2011 [107]

Answer:

For example, an earthquake of magnitude 5.5 releases about 32 times as much energy as an earthquake measuring 4.5. Another way to look at this is that it takes about 900 magnitude 4.5 earthquakes to equal the energy released in a single 6.5 earthquake.

Explanation:

8 0
2 years ago
Which equation describes the fastest runner?
irina [24]
I think the answer will be A
7 0
2 years ago
Read 2 more answers
Can someone help please
love history [14]

Answer:

The correct answer is 24.

Explanation:

4 0
3 years ago
Read 2 more answers
Calculate the TOTAL mechanical energy of pendulum is it swings from his highest point to its lowest point. Pendulum mass is 4
Lerok [7]

Answer:

its should be 2.0 and 4.5 on it

3 0
3 years ago
Why is centrifugal force is a fake force?<br>​
mash [69]

Answer:

We say fictitious because the actual source of the centrifugal acceleration is somewhat indirect and the experience one has results from the unbalanced forces acting on the reference frame, not a force. Note, it is an acceleration not a force. For instance, imagine yourself on a swing.

5 0
2 years ago
Other questions:
  • The largest planet in our solar system is
    7·2 answers
  • Calculate the heat energy needed to change the temperature of 2 kg of copper from 10°C to 110°C.
    14·2 answers
  • At a department store, you adjust the mirrors in the dressing room so that they are parallel and 6.2 ft apart. You stand 1.8 ft
    9·1 answer
  • Some plants disperse their seeds when the fruit splits and contracts, propelling the seeds through the air. The trajectory of th
    11·1 answer
  • We have a solenoid made of stainless steel with 50 turns/m. The diameter of the wire is 2mm and when stretched it is 10m. What i
    12·1 answer
  • Calculate the resistance of a 900.-watt toaster
    13·2 answers
  • You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi
    5·1 answer
  • A test charge of +2 μC is placed halfway between a charge of +6 μC and another of +4 μC separated by 10 cm. (a) What is the magn
    10·1 answer
  • A 3.9 kg ball traveling towards a soccer player at a velocity of -3.5 m/s rebounds off the soccer player's foot at a velocity of
    10·1 answer
  • 1. In a series circuit, if one bulb goes out the other blubs will stay lit.
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!