Question

An object with height h, mass M, and a uniform cross-sectional area A floats upright in a liquid with density ρ.

Answer 1

** Missing information: The vertical distance from surface of liquid to bottom of the object is sought in this question, with the condition that the object is at equilibrium **

Ans: The vertical distance = y = M/(ρA)

Explanation:

Support the vertical distance = y

Object's density = M/(A*h) (since A*h = volume)

By applying the condition, 

(M/(Ah))/ρ = y/h

M/(ρAh) = y/h

y = M/(ρA)