I think it’s physical change, because the objects aren’t changing into another substance, just changing their physical shape. Hope this helps!
Answer:
As the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Explanation:
As the object is moving towards the lens then in that case first the image will form between the focus and double the distance of focus.
So here the image is diminished
now when the object is at large distance from from lens then its image will form at focus and it is of very small size
Now as the object comes closer to the lens till the object distance is 2F the image size will increase but smaller then object size
Now when object is between F and 2F then the image size will be more than object size and it will increase to infinite magnification
So overall we can say that as the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
W is the noble gas having atomic number 10 and configuration (2,8)
x, y and z are the s block elements. They have 2,2 and 1 electrons in their outermost shell respectively.
Atomic size decreases across the period and increases down the group. Element z is having more atomic size.
Hope it helps you!!!!
For this problem, we use the Coulomb's Law. The working equation is written below:
F = kQ₁Q₂/d²
where
F is the electric force
k is a constant equal to 8.99 × 10⁹ N • m²/C²
Q is the charges for the two objects
d is he distance between the objects
Substituting the values,
F = (8.99 × 10⁹ N • m²/C²)(-15×10⁻⁶ C)(-11×10⁻⁶ C)/(180²)
F = 4.578×10⁻⁵ N
Next, we determine the gravitational force using the Law of Universal Gravitation:
F = Gm₁m₂/d²
where
F is the gravitational force
G is a constant equal to 6.67 × 10⁻¹¹ N • m²/kg²
m is the masses of the objects
d is the distance between the objects
F = (6.67 × 10⁻¹¹ N • m²/kg²)(58,000 kg)(52,000 kg)/(180²)
F = 6.2089×10⁻⁶ N
The sum of the two forces equal the net force:
Net force = 4.578×10⁻⁵ N + 6.2089×10⁻⁶ N = 1.079×10⁻⁵ N
