How much work is done when a 5 N force moves a block 4 m?
1 answer:
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Answer:
Change in potential energy = 7350 Joules
Explanation:
It is given that,
Side of cube, a = 0.5 m
Density of cube,
The cube is lifted vertically by a crane to a height of 3 m
We know that, density
So, m = d × V (V = volume of cube = a³)
m = 250 kg
We have to find the change in potential energy of the cube. At ground level, the potential energy is equal to 0.
Potential energy at height h is given by :
PE = 250 kg × 9.8 m/s² ×3 m
PE = 7350 Joules
So, change in potential energy of the cube is 7350 Joules.
Answer : The value of is 286.2 J and 286.2 J respectively.
Explanation : Given,
Moles of sample = 0.877 mol
Change in temperature = 15.7 K
First we have to calculate the heat absorbed by the system.
Formula used :
where,
q = heat absorbed by the system = ?
n = moles of sample = 0.877 mol
= Change in temperature = 15.7 K
= heat capacity at constant volume of
(diatomic molecule) =
R = gas constant = 8.314 J/mol.K
Now put all the given value in the above formula, we get:
Now we have to calculate the change in internal energy of the system.
As we know that, work done is zero at constant volume. So,
Therefore, the value of is 286.2 J and 286.2 J respectively.