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Vinil7 [7]
3 years ago
15

A horizontal spring with spring constant 200N/m is compressed by 15cm and used to launch a 2kg box across a frictionless horizon

tal surface. After the box travels some distance, the surface becomes rough. The coefficient of kinetic friction of the box on the surface is 0.2. Use work and energy to find how far the box slides across the rough surface before stopping.
Physics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:

Explanation:

Given that,

Spring constant k=200N/m

Compression x = 15cm = 0.15m

Attached mass m =2kg

Coefficient of kinetic friction uk= 0.2

The energy in the spring is given as

U =½kx²

U = ½ × 200 × 0.15²

U = 2.25J

Force in the spring is given by Hooke's law

F = ke

F = 200×0.15

F = 30N

The weight of body which is equal to the normal is give as

W = mg

W = 2 × 9.81

W = 19.62N

W = N = 19.62 Newton's 2nd Law

From law of friction,

Fr = uk•N

Fr = 0.2 × 19.62

Fr = 3.924

Using newton second law again

Fnet = F - Fr

Fnet = 30 - 3.924

Fnet = 26.076

Work done by net force is given as

W = Fnet × d

W = 26.076d

Then, the work done by this net force is equal to the energy in the spring

W = U

26.076d = 2.25

d = 2.25/26.076

d = 0.0863m

Which is 8.63cm

So the box will slide 8.63cm before stopping

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MArishka [77]

Answer:

New location at time 3.01 is given by: (7.49, 2.11)

Explanation:

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With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:

distance=v\,*\, t

distance_x=49\,(0.01)=0.49\\distance_y=11\,(0.01)=0.11

Therefore, adding these displacements in component form to the original particle's position, we get:

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6 0
3 years ago
Which of these is not measured in hertz? Select all that apply.
Wittaler [7]
A). period is time

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4 0
3 years ago
Read 2 more answers
A 9-inch tall sunflower is planted in a garden and the height of the sunflower increases exponentially. 5 days after being plant
stira [4]

Answer:

a)  h / h₀ = 1,682

, b) h / h₀ = 1.11

, c)    h / h₀ = 2.07

Explanation:

For this exercise let's look for the growth equation, as they indicate that it is exponential

        h = h₀ e^{\alpha t}

The initial height is 9 ”, so the constant

         h₀ = 9”

Let's use the given values

       h = 15.1655”

       t = 5 days

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       h = 9 e^{0.104 t}

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        h / h₀ = e^{0.104  5}

        h / h₀ = 1,682

b) for t = 1 day

       h / h₀ = e^{0.104 1}

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       h / h₀ = e^{0.104 7}

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8 0
3 years ago
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enyata [817]

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4 0
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coldgirl [10]
Refer to the diagram shown.

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Define 
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3 0
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