The maximum height reached by the ball is 99.2 m
Explanation:
When the ball is thrown straight up, it follows a free fall motion, which is a uniformly accelerated motion with constant acceleration (
towards the ground). Therefore, we can use the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem, we have:
u = 44.1 m/s is the initial vertical velocity of the ball
v = 0 is the final velocity when the ball reaches the maximum height
s is the maximum height
is the acceleration of gravity (downward, so negative)
Solving for s, we find the maximum height reached by the ball:

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Answer:
A physical change is a change to the physical—as opposed to chemical—properties of a substance. They are usually reversible. The physical properties of a substance include such characteristics as shape (volume and size), color, texture, flexibility, density, and mass.
Answer:
Option C
Explanation:
Kinetic energy is the energy that the body possesses by virtue of its motion.
The formula for Kinetic energy is given by 
Using this formula let us find kinetic energy for the bodies given and find out which is the greatest
A) KE = 
B) KE =
C) KE = 
D) KE = 
Comparing these we find that 9mv^2 is the highest.
Hence option C is the answer.
Answer:
his is an example of the transformation of gravitational potential energy into kinetic energy
Explanation:
The game of juggling bowling is a clear example of the conservation of mechanical energy,
when the bolus is in the upper part of the path mechanical energy is potential energy; As this energy descends, it becomes kinetic energy where the lowest part of the trajectory, just before touching the hand, is totally kinetic.
At the moment of touching the hand, a relationship is applied that reverses the value of the speed, that is, now it is ascending and the cycle repeats.
Therefore this is an example of the transformation of gravitational potential energy into kinetic energy
Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
P=F/A